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svetoff [14.1K]
2 years ago
14

Trigonometry questions attached, dear GOD please help.

Mathematics
1 answer:
brilliants [131]2 years ago
3 0

Answer:

like its too blury

Step-by-step explanation:

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For two events, M and N, P(M)=0.7, P(N|M)=0.3, and P(M'|N')
dexar [7]
Topic:C<span>onditional Probability

</span>For any two events A and B, where P(B) ≠ 0, P( A | B ) = P( A ∩ B ) / P( B ) = P( B | A) * P(A) / P(B)..i.e..{the probability of A given B is equal to the probability of A and B divided by the probability of B}

<span>For a set of events A1, A2, A3, ... , An,
</span>hence,
P(B) 
<span>= P(B and A1) + P(B and A2) + ... + P(B and An) </span>
= P(B | A1) * P(A1) + P(B | A2) * P(A2) + ... + P(B | An) * P(An)

P(M | N) 
<span>= P(N | M) * P(M) / P(N) </span>
<span>= P(N | M) * P(M) / (P(N | M) * P(M) + P(N | M') * (1 - P(M))) 
</span><span>Substitute Values.... you get ?

</span>
5 0
3 years ago
Two similar cones have volume of 4 m and 108 m respectively. If the large one has surface area 54 m, find the surface area of th
trasher [3.6K]

 

\displaystyle\bf\\Explanations:\\\\The~similarity~ratio~of~two~similar~cones=k\\\\k=is~the~ratio~between~2~corresponding~lengths\\\\k=\frac{R_1}{R_2}=\frac{h_1}{h_2}\\\\The~ratio~between~2~corresponding~areas~of~similar~cones=k^2\\\\\frac{Area~1}{Area~2}=k^2\\\\The~ratio~between~the~volumes~of~the~2~similar~cones=k^3\\\\\frac{Volume~1}{Volume~2}=k^3

.

\displaystyle\bf\\Solving:\\\\Volume1=108~m^3\\\\Volume2=4m^3\\\\k^3=\frac{108}{4}\\\\k^3=27~~\Big|\sqrt{~}\\\\k=\sqrt[\b3]{27}\\\\k=3\\\\Area1=54~m^2\\\\\frac{Area~1}{Area~2}=k^2\\\\\frac{54}{Area~2}=3^2\\\\\frac{54}{Area~2}=9\\\\Area2=\frac{54}{9}\\\\\boxed{\bf Area2=6 m^2}

 

4 0
3 years ago
Quadrilateral ABCD has coordinates A (3, -5), B (5, -2), C (10, -4), D (8, -7). Quadrilateral ABCD is a
Oksana_A [137]

Answer:

Step-by-step explanation:

Quadrilateral ABCD is parallelogram, because opposite sides are congruent and adjacent sides are not perpendicular.

6 0
3 years ago
How do you get angle x using trigonometry in a right angled triangle?
Scorpion4ik [409]

Answer:

Example

Step 1 The two sides we know are Adjacent (6,750) and Hypotenuse (8,100).

Step 2 SOHCAHTOA tells us we must use Cosine.

Step 3 Calculate Adjacent / Hypotenuse = 6,750/8,100 = 0.8333.

Step 4 Find the angle from your calculator using cos-1 of 0.8333:

3 0
3 years ago
What would be the answer
sashaice [31]

Answer:

I think It's option (B) 45

Step-by-step explanation:

But I am not sure It's correct or not

I hope It's helpful

6 0
2 years ago
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