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Gennadij [26K]
3 years ago
8

What's the scientific name of a leopard?

Biology
1 answer:
Kay [80]3 years ago
6 0

Answer:

Panthera pardus

Explanation:

leopard, (Panthera pardus), , also called panther, large cat closely related to the lion, tiger, and jaguar. (credit to brititanica articles)

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The first step in making a protein is to make a copy of ___in the nucleus
Luden [163]

it is DNA's Code. hope i helps

5 0
3 years ago
Assuming a cell has just completed DNA synthesis, place these stages/steps in the cell cycle in the correct order of occurance b
shusha [124]

Answer:

The division of eukaryotic cell is done through various phase known as cell cycle.

Explanation:

The two basic phases of cell cycle is Interphase and Mitosis, that can be further divided into:

1) G2 Phase; G2 checkpoint ( Interphase stage)

2) Prometaphase (Mitotic Phase)

3) Anaphase  (Mitotic Phase)

4) Telophase  (Mitotic Phase)

5) cytokinesis (Mitotic Phase)

6) G1 Phase; G1 checkpoint ( Interphase stage)

After G1 phase there would be again S phase in which DNA replication occur.

7 0
3 years ago
assume that life on Mars requires cell potential to be 100mV, and the extracellular concentrations of the three major species ar
svetlana [45]

Answer:

Explanation:

From the information given:

The cell potential on mars E = + 100 mV

By using Goldman's equation:

E_m = \dfrac{RT}{zF}In \Big (\dfrac{P_K[K^+]_{out}+P_{Na}[Na^+]_{out}+P_{Cl}[Cl^-]_{out} }{P_K[K^+]_{in}+P_{Na}[Na^+]_{in}+ P_{Cl}[Cl^-]_{in}}      \Big )

Let's take a look at the impermeable cell with respect to two species;

and the two species be Na⁺ and Cl⁻

E_m = \dfrac{RT}{zF} In \dfrac{[K^+]_{out}}{[K^+]_{in}}

where;

z = ionic charge on the species = + 1

F = faraday constant

∴

100 \times 10^{-3} = \Big (\dfrac{8.314 \times 298}{1\times 96485} \Big) \mathtt{In}  \Big ( \dfrac{4}{[K^+]_{in}}   \Big)

100 \times 10^{-3} = 0.0257 \Big ( \dfrac{4}{[K^+]_{in}}   \Big)

3.981= \mathtt{In} \Big ( \dfrac{4}{[K^+]_{in}}   \Big)

exp ( 3.981) = \dfrac{4}{[K^+]_{in}} \\ \\  53.57 = \dfrac{4}{[K^+]_{in}}

[K^+]_{in} = \dfrac{4}{53.57}

[K^+]_{in}  = 0.0476

For [Cl⁻]:

100 \times 10^{-3} = -0.0257 \  \mathtt{In} \Big ( \dfrac{120}{[Cl^-]_{in}}   \Big)

-3.981 =  \  \mathtt{In} \Big ( \dfrac{120}{[Cl^-]_{in}}   \Big)

0.01867 =  \dfrac{120}{[Cl^-]_{in}}

[Cl^-]_{in} = \dfrac{120}{0.01867}

[Cl^-]_{in} =6427.4

For [Na⁺]:

100 \times 10^{-3} = 0.0257 \Big ( \dfrac{145}{[Na^+]_{in}}   \Big)

53.57= \Big ( \dfrac{145}{[Na^+]_{in}}   \Big)

[Na^+]_{in}= 2.70

6 0
2 years ago
What is the function of the hormone erythropoietin?
xxTIMURxx [149]

Answer:

stimulates production of red blood cells is a correct answer.

Explanation:

function of the hormone erythropoietin: stimulates production of red blood cells

Erythropoietin hormone is produced by the kidney and its function is to promotes or support the formation of the red blood cells and to provide protection to the cells from the destruction.

Erythropoietin hormone stimulates the bone marrow to produce red blood cells and the function of the red blood cells is to transport oxygen to the body.

4 0
3 years ago
Free points! loll take em while ya can
andrezito [222]

Answer:

Explanation: thank you!!!

5 0
3 years ago
Read 2 more answers
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