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Nutka1998 [239]
2 years ago
7

\sf 45-2x=75-3x Free

Mathematics
2 answers:
irakobra [83]2 years ago
6 0

Answer:

<h3>aww thanks </h3>

the process by which plants and animals.make their own food is called photo synthesis.

MatroZZZ [7]2 years ago
3 0

\sf \longmapsto45 - 2x = 75 - 3x

\sf \longmapsto45+−2x=75+−3x

\sf \longmapsto−2x+45=−3x+75

\sf \longmapsto \:  −2x+45+3x=−3x+75+3x

\sf \longmapsto \: x+45=75

\sf \longmapsto \: x+45−45=75−45

\sf \longmapsto \: x=30

\boxed{\sf 30}

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Andrew [12]

Answer: -8.92

Step-by-step explanation:

4 0
3 years ago
A certain city's population is 120,000 and decreases 1.4% per year for 15 years.
mart [117]

Answer:

  • Decay Problem.
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  • Initial Amount =120,000
  • P(t)=120000(0.986)^t
  • P(10)=104,220

Step-by-step explanation:

The exponential function for growth/decay is given as:

P(t)=P_0(1 \pm r)^t, where:\\P_0$ is the Initial Population\\r is the growth/decay rate\\t is time

In this problem:

The city's initial population is 120,000 and it decreases by 1.4% per year.

  • Since the population decreases, it is a Decay Problem.
  • Decay rate, r=1.4% =0.014
  • Initial Amount =120,000

Therefore, the function is:

P(t)=120000(1 - 0.014)^t\\P(t)=120000(0.986)^t

When t=10 years

P(10)=120000(0.986)^10\\=104219.8\\\approx 104220 $ (to the nearest whole number)

8 0
3 years ago
Consider the scatter plot.
Leno4ka [110]

<u>Answer:</u>

The correct answer option is: The y-intercept of the line of best fit shows that when time started, the distance was 5 feet.

<u>Step-by-step explanation:</u>

We are given a scatter plot with a best fit line as shown on the given graph.

The equation of the best fit line is given by:

y = 0.75x + 5

So with the help of the equation and by looking at the given graph, we can conclude about the representation of the y intercept that the the y-intercept of the line of best fit shows that when time started, the distance was 5 feet.

Since the distance shown on the y axis is already 5 when the time started at 0 minutes.

4 0
3 years ago
Ms. Moran has started an investment club at BSS. $8000 is invested, some at 10%
labwork [276]
The answer can be readily calculated using a single variable, x:

Let x = the amount being invested at an annual rate of 10%
Let (8000 - x) = the amount being invested at an annual rate of 12%

The problem is then stated as:

(x * 0.10) + ((8000 - x) * 0.12) = 900
0.10(x) + ((8000 * 0.12) - 0.12(x)) = 900
0.10(x) + 960 - 0.12(x) = 900
0.10(x) - 0.12(x) = 900 - 960
-0.02(x) = -60
-0.02(x) * -100/2 = -60 * -100/2
x = 6000 / 2
x = 3000

Thus, $3,000 is invested at 10% = $300 annually; and $8,000 - $3,000 = $5,000 invested at 12% = $600 annually, which sum to $900 annual investment.
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3 years ago
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Answer:

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Step-by-step explanation:

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