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Svet_ta [14]
2 years ago
15

What’s the slope of 10,6 and 4, 1.2

Mathematics
1 answer:
Kruka [31]2 years ago
4 0

let's firstly change the 1.2 to a fraction

1.\underline{2}\implies \cfrac{12}{1\underline{0}}\implies \cfrac{6}{5} \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x_1}{10}~,~\stackrel{y_1}{6})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{\frac{6}{5}}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{\frac{6}{5}}-\stackrel{y1}{6}}}{\underset{run} {\underset{x_2}{4}-\underset{x_1}{10}}}\implies \cfrac{~~ \frac{6-30}{5}~~}{-6}\implies \cfrac{~~ \frac{-24}{5}~~}{-6}\implies \cfrac{~~ -\frac{24}{5}~~}{-\frac{6}{1}}

-\cfrac{\stackrel{4}{~~\begin{matrix} 24 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}{5}\cdot -\cfrac{1}{\underset{1}{~~\begin{matrix} 6 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}\implies \boxed{\cfrac{4}{5}}

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user100 [1]

Answer:

Fraction of fire trucks = \frac{1}{4}

Total number of toy cars = 16

Step-by-step explanation:

Fraction of sports car = \frac{2}{3}

Fraction of remaining cars =1-\frac{2}{3}=\frac{3-2}{3} =\frac{1}{3}

So,

Fraction of pick up cars = \frac{1}{4}(\frac{1}{3})=\frac{1}{12}

Therefore,

Fraction of fire trucks = \frac{1}{3}-\frac{1}{12}=\frac{4-1}{12}=\frac{3}{12}=\frac{1}{4}

That is Number of fire trucks = \frac{1}{4} ( Total number of toy cars )

Number of fire trucks = 4

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3 years ago
a. Nick deposits money in a Certificate of Deposit account (CD). The balance (in dollars) in his account t years after making th
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Answer:

(1.06)0 = 1  and positive powers of 1.06 are larger than 1, thus the minimum value N(t) attains, if t≥0, is 400.

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2 years ago
Match each spherical volume to the largest cross sectional area of that sphere
zlopas [31]

Answer:

Part 1) 324\pi\ units^{2} ------> 7,776\pi\ units^{3}

Part 2) 36\pi\ units^{2} ------> 288\pi\ units^{3}

Part 3) 81\pi\ units^{2} ------> 972\pi\ units^{3}

Part 4) 144\pi\ units^{2} ------> 2,304\pi\ units^{3}

Step-by-step explanation:

we know that

The largest cross sectional area of that sphere is equal to the area of a circle with the same radius of the sphere

Part 1) we have

A=324\pi\ units^{2}

The area of the circle is equal to

A=\pi r^{2}

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324\pi=\pi r^{2}

Solve for r

r^{2}=324

r=18\ units

Find the volume of the sphere

The volume of the sphere is

V=\frac{4}{3}\pi r^{3}

For r=18\ units

substitute

V=\frac{4}{3}\pi (18)^{3}

V=7,776\pi\ units^{3}

Part 2) we have

A=36\pi\ units^{2}

The area of the circle is equal to

A=\pi r^{2}

so

36\pi=\pi r^{2}

Solve for r

r^{2}=36

r=6\ units

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The volume of the sphere is

V=\frac{4}{3}\pi r^{3}

For r=6\ units

substitute

V=\frac{4}{3}\pi (6)^{3}

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Part 3) we have

A=81\pi\ units^{2}

The area of the circle is equal to

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81\pi=\pi r^{2}

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The volume of the sphere is

V=\frac{4}{3}\pi r^{3}

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V=\frac{4}{3}\pi (9)^{3}

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Part 4) we have

A=144\pi\ units^{2}

The area of the circle is equal to

A=\pi r^{2}

so

144\pi=\pi r^{2}

Solve for r

r^{2}=144

r=12\ units

Find the volume of the sphere

The volume of the sphere is

V=\frac{4}{3}\pi r^{3}

For r=12\ units

substitute

V=\frac{4}{3}\pi (12)^{3}

V=2,304\pi\ units^{3}

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Answer:

Looking at this, slope seems to be 2 for the graph

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