2 years ago

Mrs. Croaker's class calculated that their class frog, named Fred, jumped 23 times every day, for 14

1 answer:

5 0

Answer:

23 times 14, we can write it as 23+23+23 and so on and so forth until we have 14 23s, which if put into a caluclator will equal 23x14

Step-by-step explanation:

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Answer:

$a_{75}=-58$

Step-by-step explanation:

This is an arithmetic sequence:

$a_n=a_1+(n-1)d$

where d is the common difference and n is the index of any given term.

For the given sequence, the common difference is -1:

$15-16=-1\\14-15=-1$

Knowing both the common difference and the first term, you can write the equation for this sequence:

$a_n=16+(n-1)(-1)$

Then you can use that equation to find the 75th term:

$a_{75}=16+(75-1)(-1)\\a_{75}=16+(74)(-1)\\a_{75}=16-74\\a_{75}=-58$

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Answer:

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Step-by-step explanation:

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