Answer:
y = 0
Step-by-step explanation:
It is always a good idea to look at the question and make some observations about it. Here, you might observe ...
- all of the bases are powers of 3: 243 = 3^5; 9 = 3^2
- y is a factor of every exponent
The latter observation is important, because it means that when y=0, every exponential expression has a value of 1. Hence y = 0 is a solution.
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To solve the equation, you can write it in terms of powers of 3.
(3^5)^(-y) = (3^-5)^(3y)·(3^2)^(-2y)
3^(-5y) = 3^(-15y)·3^(-4y)
3^(-5y) = 3^(-19y)
-5y = -19y . . . . . . . . equating exponents; equivalent to taking log base 3
14y = 0 . . . . . . . . . . add 19y
y = 0 . . . . . . . . . . . one solution
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The rules of exponents we used are ...
(a^b)(a^c) = a^(b+c)
(a^b)^c = a^(bc)
1/a^b = a^-b
(6x12=) 72 months,
(6x365=) 2,190 days
<em>Let </em><em>the </em><em>two </em><em>numbers </em><em>be </em><em>3x </em><em>and </em><em>4x</em>
<em>sum </em><em>=</em><em>3x </em><em>+</em><em> </em><em>4x </em><em>=</em><em> </em><em>7x</em>
<em>7x </em><em>=</em><em> </em><em>133</em>
<em>x=</em><em> </em><em>19</em>
<em>the </em><em>numbers </em><em>are </em><em>:</em>
<em>3(</em><em>1</em><em>9</em><em>)</em><em> </em><em>=</em><em> </em><em>57</em>
<em>4(</em><em>1</em><em>9</em><em>)</em><em> </em><em>=</em><em> </em><em>76</em>
Answer:
-4/3
Step-by-step explanation:
- since the both lines are perpendicular the product of their slopes equals -1
- let m be the slope of the red line
- m*a = -1
- m = -1/a
- a = (8-5)/(0-(-4)) = 3/4
- so m = -4/3
Answer:
my guy did you repost this as I just answered this about ten minutes ago
