It hits the ground at h=0
0=-16t^2-16t+96
undistribute -16
0=-16(t^2+t-6)
factor
0=-16(t-2)(t+3)
set to zero
0=t-2
2=t
t+3=0
t=-3, nope, we can't have negative time
at t=2, or 2 seconds
Answer: j=0.4
-j+0.8=-0.9j+0.76
-j+0.8+0.9j=-0.9+0.76+0.9j
-0.1j+0.8=0.76
-0.1+0.8-0.8=0.76-0.8
-0.1j=-0.04
-0.1j/-0.1=-0.04/-0.1
j=0.4
Ya have a good day.
Answer:
y=|x-1|-1
Step-by-step explanation:
hope that helps :)
Let x and y be the numbers;
We have x + 2y = 9 and 2x + y = 21;
Then, x = 9 - 2y;
Finally, 2(9-2y) + y = 21 ;
18 - 4y + y = 21;
18 - 3y = 21;
-3y = 3;
y = - 1;
x = 9 - 2× (-1);
x = 9 + 2 ;
x = 11;
I answered the last post, the third option is correct
