Answer:
•A c-chart is the appropriate control chart
• c' = 8.5
• Control limits, CL = 8.5
Lower control limits, LCL = 0
Upper control limits, UCL = 17.25
Step-by-step explanation:
A c chart is a quality control chart used for the number of flaws per unit.
Given:
Past inspection data:
Number of units= 100
Total flaws = 850
We now have:
c' = 850/100
= 8.5
Where CL = c' = 8.5
For control limits, we have:
CL = c'
UCL = c' + 3√c'
LCL = c' - 3√c'
The CL stands for the normal control limit, while the UCL and LCL are the upper and lower control limits respectively
Calculating the various control limits we have:
CL = c'
CL = 8.5
UCL = 8.5 + 3√8.5
= 17.25
LCL = 8.5 - 3√8.5
= -0.25
A negative LCL tend to be 0. Therefore,
LCL = 0
Step-by-step explanation:
Scale Factor of UVW to XYZ
= XY/UV = YZ/VW = XZ/UW
= 21/3 = 28/4 = 14/2
= 7. (B)
Answer:
48 people
Step-by-step explanation:
First, find how many were left after the first stop:
120(0.5)
= 60
Find how many were left after the second stop:
60(0.8)
= 48
So, since the rest got off on the third stop, this means 48 people got off on the third stop.
Answer:A polynomial added to a polynomial also still gives a polymonial
<h3>
Answer: 62</h3>
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Explanation:
18 people get off, and 21 get on
We can write the 18 as -18 to indicate a loss of 18 people. The 21 as +21 to mean we gained 21 people.
The net change is -18+21 = +3 or simply 3.
After the first stop, 3 more people are on the train compared to before reaching this stop.
If x is the number of people before the stop, then x+3 is the number of people after the stop. Set this equal to 65 and solve for x.
x+3 = 65
x = 65-3
x = 62 people were on the train to begin with.
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Check:
62 people to start off
62-18 = 44 people after the 18 people get off
44+21 = 65 people after the 21 new people get on
The answer is confirmed.
