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sattari [20]
3 years ago
8

Find the area of the figure shown. Please someone helppppp

Mathematics
1 answer:
elena-s [515]3 years ago
8 0
I think it is 105 cm squared
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(7 x6 )+(8x8)-5 gives the number of slicess were sold witch describe a part of this expression what's the sum
Afina-wow [57]

Answer:

"101" seems to the appropriate response. The further explanation is provided below.

Step-by-step explanation:

The given expression is:

⇒ (7\times 6 )+(8\times 8)-5

On solving the brackets, we get

⇒ 42+64-5

On applying addition, we get

⇒ 106-5

On applying subtraction, we get

⇒ 101

3 0
2 years ago
Solve for x: 6x = 7 = 2x = 35
Sidana [21]

Answer:

x = 5.25

Step-by-step explanation:

35 + 7 = 42

6x + 2x = 8x

42 / 8x = 5.25

8 0
3 years ago
Read 2 more answers
Which net represents this solid figure? (The first picture is the solid figure the rest are the choices
tatyana61 [14]

The solid figure is represented by the second option.

Step-by-step explanation:

  • The solid figure in the question is a cuboid.
  • On opening, it will have 6 faces, each of which will be a rectangle.
  • All the corners or edges will have 90° or right angles.
  • Also, on opening, one side will have 2 other faces attached to it on top and bottom which is seen in the second figure.
3 0
3 years ago
Can y’all help me.......
ira [324]
Yes is the correct answer
6 0
3 years ago
1. Two cross roads, each of width 10 m, cut at right angles through the centre of a rectangular park of length 750
just olya [345]

Answer:

Length of the road parallel to the length of the park= 700m

Width of the road= 10m

Area of the road= l\times b=700m\times10m=7000m^2l×b=700m×10m=7000m

2

Length of the road parallel to the breadth of the park =300m

Width of the road= 10m

Area of this road= l\times b=300m\times10=3000m^2l×b=300m×10=3000m

2

Area of both the roads

=7000m^2+3000m^2-Area\ of\ the\ common\ portion\=7000m

2

+3000m

2

−Area of the common portion

=10000m^2-10m\times10m=10000m

2

−10m×10m

=10000m^2-100m^2=10000m

2

−100m

2

=9900m^2=0.99=9900m

2

=0.99

Area of the park = l\times bl×b

=700m\times300m=210000m^2=700m×300m=210000m

2

Area of the park excluding the roads

=210000m^2-9900m^2=210000m

2

−9900m

2

=200100m^2=20.01=200100m

2

=20.01

6 0
3 years ago
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