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Setler79 [48]
3 years ago
12

PLEASE HELP IT’S DUE TMR!!

Mathematics
1 answer:
iragen [17]3 years ago
3 0

4856

1.07

12.9

7.00

0.00199 (199)

0.000660 (660)

:)

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Answer with work plssss
Inessa05 [86]

Answer:

2a^4b^6

Step-by-step explanation:

a^2(ab^3)^2+b^2(a^2b^2)^2\\\\=a^2(a^2b^{2*3})+b^2(a^{2*2}b^{2*2})\\\\=a^2(a^2b^6)+b^2(a^4b^4)\\\\=a^{2+2}b^6+a^4b^{4+2}\\\\=a^4b^6+a^4b^6\\\\=2a^4b^6

6 0
3 years ago
Describe does Glide Reflection from the preimage triangle and black to the image triangle in red
AveGali [126]

Answer:

d

Step-by-step explanation:

Lets look at V which is at (2,-4).

We will also look at it's image V' which is at (-2,-1).

Let's go through the choices:

a. translation left 4 units and down 1 unit reflection x axis

Translating V left 4 and down 1 would give us (2-4,-4-1)

(-2,-5)

Reflecting that across the x-axis would give us

(-2,5).

So this is not (-2,-1) so let's move on...

b. translation left 2 units and up 2 units reflection line x=1

Translating V left 2 and up 2 gives us

(2-2,-4+2)

(0,-2)

Now reflecting this over x=1 gives us

(2,-2). ( Imagine this x=1 which is verical going right smack between points (0,-2) and (2,-2).)

We still did not reach our goal image.

c. translation left 2 units up and up 3 units reflection y axis

Starting at V(2,-4) and moving left 2 & up 3 gives (2-2,-4+3)=(0,-1).

Now reflecting this over the vertical axis, the y-axis, gives us (0,-1).

So we did not reach our (-2,-1) point yet.

d. translation left 2 units and 3 units reflection line x=-1.

​Starting at (2,-4) then moving left 2 and up 3 gives us (2-2,-4+3)=(0,-1).

Now we are reflecting over x=-1 which means we want to choose a point on the side making x=-1 the middle. Thuis point on the other side of (0,-1) of x=-1 would be (-2,-1) which is the goal.

8 0
3 years ago
After a dreary day of rain, the sun peeks through the clouds and a rainbow forms. You notice the rainbow is the shape of a parab
salantis [7]

I would not normally stop to answer this question, mainly because
there is no question asked.  It's just three statements.

I do have to stop here and leave a remark, however. 

Math and Physics are closely enough related that I would not
have expected to see what I see here.  Although the math in
this question is reasonable, the Physics is inexcusable.

A rainbow is always a part of a circle.
Rainbows are never parabolas.

You could never cut a parabola out of paper, and then
hold it up in front of you after a rainstorm, and match it
to the rainbow.
6 0
3 years ago
Read 2 more answers
A number decreased by the total of the number and fourteen
Charra [1.4K]

The answer to this would be x-(x+14)

Here's an explanation:

Let x represent the unknown number. The problem says that x has been decreased by the sum of x and 14. So, to put this in a form of an equation, it would be x-(x+14), since you have to do the addition first before you can subtract the two number since you don't know what x is. This equation is equal to -14 no matter what x is.

4 0
3 years ago
What is the measure in radians for the central angle of a circle whose radius is 8 cm and intercepted arc length is 7.2 cm? Ente
natulia [17]

The measure in radians for the central angle of the circle is; 0.9 radians.

<h3>What is the angle measure in radians of the central angle?</h3>

Since, the length of the arc is given as 7.2cm and it's radius is 8cm.

It follows that the angle measure of the central angle can be evaluated as follows;

7.2 = (A/6.28) × 2× 3.14 × 8

7.2 = 8A

A = 7.2/8

A = 0.9 radians.

Read more on radian measure;

brainly.com/question/19758686

#SPJ1

8 0
1 year ago
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