The answer is c, because it is the same line, just higher.
The equation of the line g that passes through points (-3, 2) and (0, 5), in slope-intercept form, is: y = x + 5.
<h3>How to Write the Equation of a Line in Slope-intercept Form?</h3>
Given the coordinates of two points that lie on a straight line on a graph, the equation that represents the line in slope-intercept form can be expressed as, y = mx + b, where:
Slope = m = change in y / change in x
y-intercept = b (the value of y when x = 0).
The coordinates of the two points on line g is given as:
(-3, 2) = (x1, y1)
(0, 5) = (x2, y2).
Find the slope (m) of the line:
Slope (m) = (5 - 2)/(0 - (-3))
Slope (m) = 3/3
Slope (m) = 1.
Y-intercept (b) = 5
Substitute m = 1 and = 5 into y = mx + b:
y = x + 5
The equation of the line in slope-intercept form is: y = x + 5.
Learn more about the slope-intercept equation on:
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Y=5 because you add 4+1=5
6 is the anwser to ur question
Answer:
B) The maximum y-value of f(x) approaches 2
C) g(x) has the largest possible y-value
Step-by-step explanation:
f(x)=-5^x+2
f(x) is an exponential function.
Lim x→∞ f(x) = Lim x→∞ (-5^x+2) = -5^(∞)+2 = -∞+2→ Lim x→∞ f(x) = -∞
Lim x→ -∞ f(x) = Lim x→ -∞ (-5^x+2) = -5^(-∞)+2 = -1/5^∞+2 = -1/∞+2 = 0+2→
Lim x→ -∞ f(x) = 2
Then the maximun y-value of f(x) approaches 2
g(x)=-5x^2+2
g(x) is a quadratic function. The graph is a parabola
g(x)=ax^2+bx+c
a=-5<0, the parabola opens downward and has a maximum value at
x=-b/(2a)
b=0
c=2
x=-0/2(-5)
x=0/10
x=0
The maximum value is at x=0:
g(0)=-5(0)^2+2=-5(0)+2=0+2→g(0)=2
The maximum value of g(x) is 2
