A cube shaped pool is half full of water. If the water is 36 inches deep, how much would the water in the pool weigh if the pool
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The margin of error for 324 adults surveyed with 1.6 standard deviations is 0.1742.
<h3>What is the margin of error?</h3>The margin of error can be defined as the amount of random sampling error in the results of a survey. It is given by the formula,
= margin of error
= confidence level
= quantile
σ = standard deviation
n = sample size
As it is given that the sample size of the survey is 324, while the standard deviation of the survey is 1.6.
We know that the value of the z for 95% confidence interval is 1.96. Therefore, using the formula of the standard of error we can write it as,
Hence, the margin of error for 324 adults surveyed with 1.6 standard deviations is 0.1742.
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Answer:
Probability that the average salary of the 400 players exceeded $1.1 million is 0.99999.
Step-by-step explanation:
We are given that one year, professional sports players salaries averaged $1.5 million with a standard deviation of $0.9 million.
Suppose a sample of 400 major league players was taken.
<em>Let </em><em> = sample average salary</em>
The z-score probability distribution for sample mean is given by;
Z = ~ N(0,1)
where, = mean salary = $1.5 million
= standard deviation = $0.9 million
n = sample of players = 400
The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.
So, probability that the average salary of the 400 players exceeded $1.1 million is given by = P( > $1.1 million)
P( > $1.1 million) = P(
>
) = P(Z > -8.89) = P(Z < 8.89)
<em>Now, in the z table the maximum value of which probability area is given is for critical value of x = 4.40 as 0.99999. So, we can assume that the above probability also has an area of 0.99999 or nearly close to 1.</em>
Therefore, probability that the average salary of the 400 players exceeded $1.1 million is 0.99999.