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Bezzdna [24]
3 years ago
8

A cube shaped pool is half full of water. If the water is 36 inches deep, how much would the water in the pool weigh if the pool

were filled to the brim? (1 cube foot weighs 56 pounds)
Mathematics
1 answer:
solmaris [256]3 years ago
5 0
36 inches = half the depth of the pool , so depth of pool = 72 inches = 6 ft
Volume of the cube = 6^3 = 216 cu ft
weight of the water = 216 * 56 pounds
  =   12096 pounds
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draw a line representing the rise and a line representing the run of the line. State the slope of the line in simplest form
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m = -1

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irina1246 [14]

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Step-by-step explanation:

3 0
3 years ago
Evaluate the integral by changing to polar coordinatesye^x dA, where R is in the first quadrant enclosed by the circle x^2+y^2=2
34kurt
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|\det J|=\left|\begin{vmatrix}\mathbf x_r&\mathbf x_\theta\\\mathbf y_r&\mathbf y_\theta\end{vmatrix}\right|=|r|

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\displaystyle\int_{r=0}^{r=5}\int_{\theta=0}^{\theta=\pi/2}r^2\sin\theta e^{r\cos\theta}\,\mathrm d\theta\,\mathrm dr

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4 years ago
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