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3 years ago

Cao nhân giải hộ với ngu toán quá

Mathematics

1 answer:

aleksandrvk [35]3 years ago

8 0

2 + 10 +7+76+5 = 3927

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Use the graph to find the midpoint between O and H.

butalik [34]

Answer:

(-1, 4)

Step-by-step explanation:

-5+3/2 = -1

6+ 2/2 = 4

(-1, 4)

3 0

3 years ago

Two adjacent sides of a parallelogram

saveliy_v [14]

Answer:

6748'

Step-by-step explanation:

The long diagonal is the third leg of a triangle with the given side lengths and an angle between them that is the supplement of the given angle. Its length can be found from the Law of Cosines.

a^2 = b^2 +c^2 -2bc·cos(A)

a^2 = 3473^2 +4822^2 -2·3473·4822·cos(180° -72.23°)

a^2 = 45,535,553.83

a ≈ 6748.004

The longer diagonal is about 6758 feet long.

5 0

3 years ago

Find the area of the figure. Use 3.14 for it.

Tcecarenko [31]

Answer:

963.73 m²

Step-by-step explanation:

To Find :-

Area of the figure

Solving :-

Area (figure) = Area (triangle) + Area (semicircle)

= 1/2bh + 1/2πr²

= 1/2 (30 x 34 + 3.14 x 17 x 17)

= 1/2 (1020 + 289 x 3.14)

= 1/2 (1020 + 907.46)

= 1/2 (1927.46)

= 963.73 m²

4 0

2 years ago

Willis bought a gallon of paint he painted a wall that is 9 feet high and 10 feet wide. Then he used the rest of the paint to pa

Lana71 [14]

Divide 560,444 by 350

560,444/350 = 1601

(This number was actually a decimal but you can't order decimal amount of paint so we round!)

7 0

3 years ago

from the top of a 120-foot high tower an air traffic controller observes an airplane on the runway at an angle of depression of

Crazy boy [7]

Data:
h (Tower height) = 120 ft
d (Distance from the base of the tower to the airplane) = ?
 $\alpha$ (Angle formed from observation of the tower to the airplane)=19º

Data: tg 19º ≈ 0.34

Note: The angle formed is tangent to the height of the tower and the distance from the base of the tower to the airplane.

Formula:
 $tg \alpha = \frac{opposite\:leg}{adjacent\:leg}$

Solving:
 $tg \alpha = \frac{opposite\:leg}{adjacent\:leg}$
$tg 19^0 = \frac{h}{d}$
$tg 19^0 = \frac{120}{d}$
$0.34 = \frac{120}{d}$
$0.34*d = 120$
$0.34d = 120$
$d = \frac{120}{0.34}$
$\boxed{\boed{d \approx 352.9\:ft}}\end{array}}\qquad\quad\checkmark$

Answer:
Distance from the base of the tower to the airplane is aproximately 352.9 ft

6 0

3 years ago