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Answer:
a) -4
b) 1
c) 1
Step-by-step explanation:
a) The matrix A is given by:
![A=\left[\begin{array}{ccc}-3&0&1\\2&-4&2\\-3&-2&1\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%260%261%5C%5C2%26-4%262%5C%5C-3%26-2%261%5Cend%7Barray%7D%5Cright%5D)
to find the eigenvalues of the matrix you use the following:

where lambda are the eigenvalues and I is the identity matrix. By replacing you obtain:
![A-\lambda I=\left[\begin{array}{ccc}-3-\lambda&0&1\\2&-4-\lambda&2\\-3&-2&1-\lambda\end{array}\right]](https://tex.z-dn.net/?f=A-%5Clambda%20I%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3-%5Clambda%260%261%5C%5C2%26-4-%5Clambda%262%5C%5C-3%26-2%261-%5Clambda%5Cend%7Barray%7D%5Cright%5D)
and by taking the determinant:
![[(-3-\lambda)(-4-\lambda)(1-\lambda)+(0)(2)(-3)+(2)(-2)(1)]-[(1)(-4-\lambda)(-3)+(0)(2)(1-\lambda)+(2)(-2)(-3-\lambda)]=0\\\\-\lambda^3-6\lambda^2-12\lambda-16=0](https://tex.z-dn.net/?f=%5B%28-3-%5Clambda%29%28-4-%5Clambda%29%281-%5Clambda%29%2B%280%29%282%29%28-3%29%2B%282%29%28-2%29%281%29%5D-%5B%281%29%28-4-%5Clambda%29%28-3%29%2B%280%29%282%29%281-%5Clambda%29%2B%282%29%28-2%29%28-3-%5Clambda%29%5D%3D0%5C%5C%5C%5C-%5Clambda%5E3-6%5Clambda%5E2-12%5Clambda-16%3D0)
and the roots of this polynomial is:

hence, the real eigenvalue of the matrix A is -4.
b) The multiplicity of the eigenvalue is 1.
c) The dimension of the eigenspace is 1 (because the multiplicity determines the dimension of the eigenspace)
Answer: 7/12!
Step-by-step explanation: 7/9 times 21/28 = 147/252. But you have to reduce it (simplify it) by dividing both the numerator and denominator by the greatest common factor and you get 7/12! Hope this helped.
There are an infinite number of solutions, so I don't plan to list them all.
I'll list two of them, and then describe how to get all of the rest.
You said that <u>2cos(x) - 1 = 0</u>
Add 1 to each side: 2cos(x) = 1
Divide each side by 2: cos(x) = 1/2
The angles whose cosine is 1/2 are 60 degrees, 300 degrees,
and any multiple of 360 degrees added to either of those.
Given:
The figures cylinder, cube, cone, and pyramid.
To find:
The formula of volume for the given figures.
Solution:
Volume of a cylinder is:

Where r is the radius and h is the height.
Volume of a cube is:

Where a is side length of cube.
It is also written as:

Where l is length, w is width, h is height and
.
Volume of a cone is:

Where r is the radius and h is the height.
Volume of a pyramid is:

Where B is the base area and h is the height.
Therefore the table of formulae is shown below:
Figure Volume formula
Cylinder 
Cube 
Cone 
Pyramid 