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andre [41]
2 years ago
15

Can someone put an answer for each box plzzzz.

Mathematics
1 answer:
Dahasolnce [82]2 years ago
7 0
We need the drop down options..
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Our product is equal to 6+2 what factors are we?
Burka [1]
4 and 2 since 6+2 is 8 and 8 has two factors which are 4 and 2.
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3 years ago
Kelly needs 2 skeins of yarn for her knitting projects. A skein of yarn is usually $9, but Casey looks for sales. Which of the f
MAXImum [283]

Answer:B the cost would be $11

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
(84x - 69y) - (65x + 34y)
Svetach [21]

(84x - 69y) - (65x + 34y)

Remove the parenthesis and combine the like terms:

84x - 65x = 19x

-69y - 34y = -103y

Combine for final answer:

19x -103y

6 0
3 years ago
2/10 + 7 = 10<br> two over 10 plus 7 equals 10<br> pls help me solve the enquality
koban [17]
If this is a true or false question, it’s false because 2/10 + 7 ≠ 10. the correct inequality would be 2/10 + 7 = 12.
4 0
3 years ago
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A small lawnmower company produced 1,500 lawnmowers in 2008. In an effort to determine how maintenance-free these units were, th
ikadub [295]

Answer:

The 95% confidence interval for the average number of years until the first major repair is (3.1, 3.5).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the average using the finite correction factor is:

CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\cdot\sqrt{\frac{N-n}{N-1}}

The information provided is:

N=1500\\n=183\\\sigma=1.47\\\bar x=3.3

The critical value of <em>z</em> for 95% confidence level is,

<em>z</em> = 1.96

Compute the 95% confidence interval for the average number of years until the first major repair as follows:

CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\cdot\sqrt{\frac{N-n}{N-1}}

     =3.3\pm 1.96\times\frac{1.47}{\sqrt{183}}\times\sqrt{\frac{1500-183}{1500-1}}\\\\=3.3\pm 0.19964\\\\=(3.10036, 3.49964)\\\\\approx (3.1, 3.5)

Thus, the 95% confidence interval for the average number of years until the first major repair is (3.1, 3.5).

7 0
3 years ago
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