2 years ago

Can someone put an answer for each box plzzzz.

Mathematics

1 answer:

Dahasolnce [82]2 years ago

7 0

We need the drop down options..

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Our product is equal to 6+2 what factors are we?

Burka [1]

4 and 2 since 6+2 is 8 and 8 has two factors which are 4 and 2.

6 0

3 years ago

Kelly needs 2 skeins of yarn for her knitting projects. A skein of yarn is usually $9, but Casey looks for sales. Which of the f

MAXImum [283]

Answer:B the cost would be $11

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

(84x - 69y) - (65x + 34y)

Svetach [21]

(84x - 69y) - (65x + 34y)

Remove the parenthesis and combine the like terms:

84x - 65x = 19x

-69y - 34y = -103y

Combine for final answer:

19x -103y

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3 years ago

2/10 + 7 = 10 two over 10 plus 7 equals 10 pls help me solve the enquality

koban [17]

If this is a true or false question, it’s false because 2/10 + 7 ≠ 10. the correct inequality would be 2/10 + 7 = 12.

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3 years ago

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A small lawnmower company produced 1,500 lawnmowers in 2008. In an effort to determine how maintenance-free these units were, th

ikadub [295]

Answer:

The 95% confidence interval for the average number of years until the first major repair is (3.1, 3.5).

Step-by-step explanation:

The (1 - α)% confidence interval for the average using the finite correction factor is:

$CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\cdot\sqrt{\frac{N-n}{N-1}}$

The information provided is:

$N=1500\\n=183\\\sigma=1.47\\\bar x=3.3$

The critical value of z for 95% confidence level is,

z = 1.96

Compute the 95% confidence interval for the average number of years until the first major repair as follows:

$CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\cdot\sqrt{\frac{N-n}{N-1}}$

$=3.3\pm 1.96\times\frac{1.47}{\sqrt{183}}\times\sqrt{\frac{1500-183}{1500-1}}\\\\=3.3\pm 0.19964\\\\=(3.10036, 3.49964)\\\\\approx (3.1, 3.5)$

Thus, the 95% confidence interval for the average number of years until the first major repair is (3.1, 3.5).

7 0

3 years ago