Answer:
Step-by-step explanation:
first distribute the ^3, -3^3=-27, for the variables, (x^y)^3=x^(3y) so (b^2)^3=b^6 and (c^-6)^3=c^-18. now we have . Next we have to get rid of the negative in c^-18. x^-y=1/x^y so c^-18=, plug it in and you get
The volume of the cylinder is 128, rounded to the nearest tenth is 130
<span>|3x| = 12 actually represents two equations: 3x = 12 and -3x = 12.
Thus, the solutions are {-4, 4).</span>
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