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gavmur [86]
3 years ago
15

What is (-2) power 5?

Mathematics
2 answers:
il63 [147K]3 years ago
6 0

Answer:

-32

Step-by-step explanation:

-2 to the power of 5 is -32

Olegator [25]3 years ago
3 0

Answer:

-32

PA BRAINLIEST

Step-by-step explanation:

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Find the vertex of the function given below.<br><br> y= x2 - 6x +1
Helga [31]

Answer:

V( 3, -8 )

Step-by-step explanation:

Parable equation is of the form:

( x - h )² = 4p*(y - k)

In that expression, vertex has coordinates V ( h, k )

Then all we have to do is transform the given equation

y = x² - 6x + 1       or     x² - 6x  = y - 1          (1)

We can get a  perfect square trinomial in the first member of the equation according to:

x²  -  6x   =   ( x - 3 )²  - 9

(x - 3 )²   = x² - 6x  + 9

By substitution  en equation (1)

( x - 3 )² - 9 = y - 1

( x - 3 )² = y -1 + 9

( x - 3 )² = y + 8

( x - 3 )² = (y + 8 )

Then vertex coordinates are

V( 3 , -8)

3 0
3 years ago
Tan(42)= x over 16<br> I need the answer and how ya got it pleasee
xz_007 [3.2K]

Answer:

14.40646471 =x

Step-by-step explanation:

tan (42) = x/16

Multiply each side by 16

16 tan 42 = x/16 *16

16 tan 42 = x

16 * .900404044 = x

14.40646471 =x

7 0
4 years ago
Arrange the systems of equations in order from least to greatest based on the number of solutions for each system.
Rama09 [41]

Answer:

work is shown and pictured

8 0
3 years ago
6(a+2b+3c)=??????????????
IrinaVladis [17]

Answer:

6(a) + 12(b) + 18(c)

Step-by-step explanation:

7 0
3 years ago
Subtract.(8j³ + 9j² + 6j + 8) - (j² + 8)
german

As we did in the previous problem, we need to remove the parenthesis using distributive property so as to be able to combine like terms.

The first paranthesis is positive, so nothing changes as we remove it:

8 j^3 + 9 j^2 + 6 j + 8 - (j^2 + 8)

before removing the second parenthesis, we realize it is preceded by the negative sign of the indicated subtraction. Then as we remove the parenthesis, we flip the signs of all terms inside it:

8 j^3 + 9 j^2 + 6 j + 8 - j^2 - 8

now we combine like terms + 8 and - 8, rendering a zero "0". and we also combine the terms that contain j^2 : 9 j^2 - j^2 = 8 j^2.

Therefore, our final expression becomes:

8 j^3 + 8 j^2 + 6 j

3 0
1 year ago
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