<em>IMPORTANT THIGNS TO REMEMBER:</em>
- Has 20 lb. dog food!
- Gives dog 1 3/5 everyday!
- Find how much eaten after 2 days!
- Find how much is left!
<em>ANSWER:</em>
Dog has eaten 3 1/5 after 2 days!
There is 16 4/5 left in bag!
<em>EXPLANATION:</em>
Since she gives 1 3/5 to her dog everyday and their asking for 2 days you would multiply 1 3/5 × 2 OR add 1 3/5 + 1 3/5
Which would give you 3 1/5
So, the dog has eaten 3 1/5 lb. of dog food in 2 days.
However then, you would subtract 20 lb. - 3 1/5 lb. because there is 20 lb. dog food in all and the dog has eaten 3 1/5 of it. This would give you 16 4/5 lb.
Meaning there is 16 4/5 lb. left in the bag of dog food!
Linear functions can be written in the form y=mx+b, where:
y is a y coordinate on the line
m is the slope of the line
x is the x coordinate on the line that corresponds with the y coordinate in the equation
b is the y-intercept of the line
So for the equation y=-10x+1:
m=-10 and b=1 so the slope of the line is -10, and the y-intercept is 1. Your answer is B.
A=148°
B=148°
Step-by-step explanation:
180-38=148°
because A and B are equal, they're both 148°
Answer:
(C)72.4 in
Step-by-step explanation:
Given an acute triangle in which the longest side measures 30 inches; and the other two sides are congruent.
Consider the attached diagram
AB=BC=x
However to be able to solve for x, we form a right triangle with endpoints A and C.
Since the hypotenuse is always the longest side in a right triangle
Hypotenuse, AC=30 Inches
Using Pythagoras Theorem
Therefore, the smallest possible perimeter of the triangle
Perimeter=2x+30
=2(21.21)+30
=42.42+30
=72.4 Inches (rounded to the nearest tenth)
Answer:
Therefore, the four intervals are
(1) 6 - 6.59
(2) 7 - 7.59
(3) 8 - 8.59
(4) 9 - 9.59
The four frequencies are
(1) 4
(2) 3
(3) 1
(4) 6
Step-by-step explanation:
From the data, we have
Interval Frequency
1st 6 - 6.59 4
2nd 7 - 7.59 3
3rd 8 - 8.59 1
4th 9 - 9.59 6
Therefore, the four intervals are
(1) 6 - 6.59
(2) 7 - 7.59
(3) 8 - 8.59
(4) 9 - 9.59
The four frequencies are
(1) 4
(2) 3
(3) 1
(4) 6
