Let width and length be x and y respectively.
Perimeter (32in) =2x+2y=> 16=x+y => y=16-x
Area, A = xy = x(16-x) = 16x-x^2
The function to maximize is area: A=16 x-x^2
For maximum area, the first derivative of A =0 => A'=16-2x =0
Solving for x: 16-2x=0 =>2x=16 => x=8 in
And therefore, y=16-8 = 8 in
I got b i did this question before but dont take my word for it im not one hundred percent sure
Parallel = same slope
Find slope of 3x + 5y = 8
Turn into y = mx + b
5y = -3x + 8
Divide by 5
y = -3/5x + 8/5
Slope is -3/5
Y = -3/5x + b, find y intercept
Plug in the point
4 = -3/5(10) + b
4 = -6 + b, b = 10
Final equation: y = -3/5x + 10
-13/5. The equation to find the slope between 2 points is y sub 2-y sub 1/x sub 2-x sub 1. Or in this case, -6-7/2+3. -6-7=-13, 2+3=5. So the slope is -13/5.