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3 years ago

Which of these is a step in constructing and inscribed regular hexagon using technology?

Mathematics

2 answers:

artcher [175]3 years ago

7 0

Answer;

A. Create circle B with radius AB.

Explanation .

-This is the first step for the construction of an inscribed regular hexagon (Creating a circle B with radius AB). The next step is using the given center and the straightedge to construct a radius of the circle and use the compass to measure the radius. and the process continues.

kotegsom [21]3 years ago

7 0

For creating regular hexagon the first step is
Create circle B with radius AB.

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Find the value of x. Round to the nearest tenth. 26 12 х X= = [?]

levacccp [35]

Answer:

X = 5.9 (in degree mode)

Step-by-step explanation:

Do the following:

12(tan26) = X

Plugging this into a calculator, you will get:

X = 5.9 (in degree mode)

7 0

3 years ago

What is the average rate of change of the function over the interval x = 0 to x = 6? f(x)=2x−1 3x+5 Enter your answer, as a frac

Tatiana [17]

Answer:

-11

Step-by-step explanation:

Our function is 2x-13x+5

2x-13x+5= -11x+5
F(0)= 5 and F(6)= -11*6+5 = -61
let m be the average change : m= (-61-5)/6= -11

8 0

3 years ago

If (2x,3y) =(8, 9),find x and y

solong [7]

Answer:

x = 4, y = 3

Step-by-step explanation:

Equating corresponding coordinates , gives

2x = 8 ( divide both sides by 2 )

x = 4

and

3y = 9 ( divide both sides by 3 )

y = 3

5 0

3 years ago

Litter such as leaves falls to the forest floor, where the action of insects and bacteria initiates the decay process. Let A be

Travka [436]

Answer:

D = L/k

Step-by-step explanation:

Since A represents the amount of litter present in grams per square meter as a function of time in years, the net rate of litter present is

dA/dt = in flow - out flow

Since litter falls at a constant rate of L grams per square meter per year, in flow = L

Since litter decays at a constant proportional rate of k per year, the total amount of litter decay per square meter per year is A × k = Ak = out flow

So,

dA/dt = in flow - out flow

dA/dt = L - Ak

Separating the variables, we have

dA/(L - Ak) = dt

Integrating, we have

∫-kdA/-k(L - Ak) = ∫dt

1/k∫-kdA/(L - Ak) = ∫dt

1/k㏑(L - Ak) = t + C

㏑(L - Ak) = kt + kC

㏑(L - Ak) = kt + C' (C' = kC)

taking exponents of both sides, we have

$L - Ak = e^{kt + C'} \\L - Ak = e^{kt}e^{C'}\\L - Ak = C"e^{kt} (C" = e^{C'} )\\Ak = L - C"e^{kt}\\A = \frac{L}{k} - \frac{C"}{k} e^{kt}$

When t = 0, A(0) = 0 (since the forest floor is initially clear)

$A = \frac{L}{k} - \frac{C"}{k} e^{kt}\\0 = \frac{L}{k} - \frac{C"}{k} e^{k0}\\0 = \frac{L}{k} - \frac{C"}{k} e^{0}\\\frac{L}{k} = \frac{C"}{k} \\C" = L$

$A = \frac{L}{k} - \frac{L}{k} e^{kt}$

So, D = R - A =

$D = \frac{L}{k} - \frac{L}{k} - \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{kt}$

when t = 0(at initial time), the initial value of D =

$D = \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{k0}\\D = \frac{L}{k} e^{0}\\D = \frac{L}{k}$

4 0

3 years ago

. You work at a department store and make $9 per hour plus 12% commission

Luda [366]

Start with hours worked 6 x $9 = 54
Then commission $700 x 0.12 (12% converted to a decimal) = $84
Add up 54 + 84 = $138 total income

So answers are A, the first C (you make $84 in commission), and the last one, you make $138 in total.

5 0

3 years ago