Answer:
the distance from home to hardware store = (3030/60) * 88= 4444miles
time to travel back at a speed of 24mph = 4444miles /24mph = 11110 minutes
Answer:
The standard deviation of the sampling distribution of sample means would be 0.8186.
Step-by-step explanation:
We are given that
Mean of population=23.2 pounds
Standard deviation of population=6.6 pounds
n=65
We have to find the standard deviation of the sampling distribution of sample means.
We know that standard deviation of the sampling distribution of sample means
=
Using the formula
The standard deviation of the sampling distribution of sample means
=

Hence, the standard deviation of the sampling distribution of sample means would be 0.8186.
Step-by-step explanation:
1. You already got the first step, where D is the midpoint of AC and AB is congruent to BC, since it's given.
2. AD will be congruent to DC, via the definition of a midpoint (a midpoint is the middle point of a line segment, and it splits the segment into two congruent parts)
3. BD is equal to BD, via reflexive property. ( It's a shared side between the two triangles)
4. that means that ΔADB ≅ΔCDB via SSS rule.
5. ∠ABD ≅∠CDB by CPCTC (corresponding parts of congruent triangles are congruent)
Hope this helps! :)
1. $1.23 per pair
A dozen is 12 so you do 12x7=84
Then you do 103.32 divided by 84 which gives you 1.23
2. His error was doing 103.32 divided by 7 because he thought it was only 7 pairs but it’s 7 dozen.
I hope this helps you
✔cos^2A+sin^2A=1
✔1-cos^2A=sin^2A
✔cos2A=cos^2A-sin^2A
✔sin2A=2.sinA.cosA
secA=1/cosA
tgA=sinA/cosA
sin^2A/1/cos^2A-sin^2A/cos^2A
sin^2A.cos^2A/cos2A
2.sin^2A.cos^2A/cos2A
sin2A.2.sin2A/cos2A
tg2A.2.sin2A