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Kitty [74]
2 years ago
12

Find the pressure if a force of 750 N acts on an area of 12 cm3

Mathematics
1 answer:
Leto [7]2 years ago
5 0
The answer is P=F/A I had a quiz on these
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The vertices of a rectangle are A(-4,-3) b(-4,-1)C(-1,-1)d(-1,-3)
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Step-by-step explanation:

a: A(4,-3) B(4,-1) C(1,-1) D(1,-3)

b: A(-4,3) B(-4,1) C(-1,1) D(-1, 3)

c:yes because you are just changing the direction not the shape or size

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3 years ago
The scores on an exam are normally distributed with a mean of 77 and a standard deviation of 10. What percent of the scores are
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<span>The correct answer between all the choices given is the second choice, which is 16%. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.</span>

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3 years ago
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timofeeve [1]

1. -2<2 2. -4> -5. -20<20. -7>-8. -10<-1. 50>-100

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3 years ago
In the diagram below, BD is parallel to XY. What is the value of y?
galben [10]

Answer:

67 degrees

Step-by-step explanation:

alternate exterior angles are always congruent

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3 years ago
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The U.S. Census Bureau conducts a study to determine the time needed to complete the short form. The Bureau surveys 200 people.
NISA [10]

Answer:

8.2-2.58\frac{2.2}{\sqrt{18}}=6.86    

8.2+2.58\frac{2.2}{\sqrt{18}}=9.54    

So on this case the 90% confidence interval would be given by (6.86;9.54)    And the error is given by:

ME= 2.58\frac{2.2}{\sqrt{18}} =1.338

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=8.2 represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=2.2 represent the population standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that z_{\alpha/2}=2.58

Now we have everything in order to replace into formula (1):

8.2-2.58\frac{2.2}{\sqrt{18}}=6.86    

8.2+2.58\frac{2.2}{\sqrt{18}}=9.54    

So on this case the 90% confidence interval would be given by (6.86;9.54)    And the error is given by:

ME= 2.58\frac{2.2}{\sqrt{18}} =1.338

8 0
3 years ago
Read 2 more answers
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