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3 years ago

Graph the system of equations. { 8x+8y=64 2x−2y=−4

Mathematics

2 answers:

siniylev [52]3 years ago

8 0

What you do is you rearrange and simplify both equations to have them in terms of y, and then graph them. If it asked for a solution, their point of intersection would be the solution.

fiasKO [112]3 years ago

5 0

Answer: graph 3,5 and 8,8

Step-by-step explanation:

i took the test

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4-7x +3 +5x pleas help thanks

meriva

Answer:

7−2x

Step-by-step explanation:

1 Collect like terms.

(4+3)+(-7x+5x)

(4+3)+(−7x+5x)

2 Simplify.

7-2x

7−2x

3 0

2 years ago

Read 2 more answers

Translate the following phrase into an algebraic expression. Use the

marissa [1.9K]

Answer:

8+n/3

Step-by-step explanation:

$\frac{8+n}{3}$

8 0

3 years ago

How do you simplify this expression step by step?

nataly862011 [7]

$\bf \textit{Pythagorean Identities} \\\\ sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{csc(\theta )-sin(\theta )}{cos(\theta )}\implies \cfrac{~~\frac{1}{sin(\theta )}-sin(\theta )~~}{cos(\theta )}\implies \cfrac{~~\frac{1-sin^2(\theta )}{sin(\theta )}~~}{cos(\theta )}$

$\bf \cfrac{1-sin^2(\theta )}{sin(\theta )}\cdot \cfrac{1}{cos(\theta )}\implies \cfrac{\stackrel{cos(\theta )}{\begin{matrix} cos^2(\theta ) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}} }{sin(\theta )}\cdot \cfrac{1}{\begin{matrix} cos(\theta ) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix} }\implies \cfrac{cos(\theta )}{sin(\theta )}\implies cot(\theta )$

5 0

3 years ago

Read 2 more answers

Find the second derivative of 2x^3-3y^2=8

Umnica [9.8K]

Answer:

$\frac{d^2y}{dx^2}=\frac{x(2y-x^3)}{y^3}$

Step-by-step explanation:

Find the first implicit derivative using implicit differentiation

$2x^3-3y^2=8\\\\6x^2-6y\frac{dy}{dx}=0\\ \\-6y\frac{dy}{dx}=-6x^2\\ \\\frac{dy}{dx}=\frac{x^2}{y}$

Use the substitution of dy/dx to find the second derivative (d²y/dx²)

$\frac{d^2y}{dx^2}=\frac{(y)(2x)-(x^2)(\frac{dy}{dx})}{y^2}\\ \\\frac{d^2y}{dx^2}=\frac{2xy-(x^2)(\frac{x^2}{y})}{y^2}\\\\\frac{d^2y}{dx^2}=\frac{2xy-\frac{x^4}{y}}{y^2}\\\\\frac{d^2y}{dx^2}=\frac{x(2y-x^3)}{y^3}$

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2 years ago

Can someone plzzz help with this ill give a pizza :((

nydimaria [60]

$22 \times 18 = (20 + 2)(20 - 2) = {20}^{2} - {2}^{2} = 396$

7 0

2 years ago