Answer:
21.897 to the nearest hundredth is 2.19
Each team needs two people for a 3-legged race.
Therefore, the number of orders (combinations) of 2 people at a time from 8 is
₈C₂ = 8!/(2!6!)
= (8*7*6!)/(2*6!)
= (8*7)/2
= 56/2
= 28
Answer: 28
The answer is <span>2.5 × 10⁻⁹ × 1.5 × 10³ = 3.75 × 10⁻⁶ </span>
