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2 years ago

N^2+6n+c Find the value of c that completes the square

Mathematics

1 answer:

Anon25 [30]2 years ago

6 0

Answer:

The value of ”c” can by found by this formula: (b/2)^2. In this equation the ”b” is 6. So, (6/3)^2=3^2=9.

The value of “c” that completes the square is 9.

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mart [117]

Answer:

Step-by-step explanation:

refer the attachment

to solve the question we need to recall one of the most important theorem of circle known as two tangent theorem which states that tangents which meet at the same point are equal that is being said

FA=AI=17
CH=CG=2.5

since $\rm BA=FA+FB$ and it's given that FA and BA are 17 and 29 FB should be

$\rm 29=17+FB$

therefore,

$FB=29-17=\boxed{12}$

once again by two tangent theorem we acquire:

$FB=BH=\boxed{12}$

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12+2.5
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thus,

DI=21-17= $\boxed{4}$

By the theorem we obtain:

DI=DG=4

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DC=4+2.5= $\boxed{6.5}$

Now finding the Perimeter of ABCD

$P_{\text{ABCD}}=\text{AB+AD+BC+DC}$

substitute what we have and got

$P_{\text{ABCD}}=\text{29+21+14.5+6.5}$

simplify addition:

$P_{\text{ABCD}}=\boxed{71}$

hence,

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3 years ago

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How you would solve this problem is:

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Answer:

Step-by-step explanation:

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3 years ago