Sum of 2 perfect cubes
a³+b³=(a+b)(x²-xy+y²)
so
x³+4³=(x+4)(x²-4x+16)
set each to zero
x+4=0
x=-4
the other one can't be solveed using conventional means
use quadratic formula
for
ax^2+bx+c=0
x=

for x²-4x+16=0
x=

x=

x=

x=

x=

x=

the roots are
x=-4 and 2+2i√3 and 2-2i√3
Answer:
1. -18x¹¹
2. 3n⁷
Step-by-step explanation:
For these problems, there are two things you need to worry about: negative signs and exponents.
1. Let's look at the signs first. There is only one value with a negative sign, meaning that the negative sign will stay.
When multiplying with exponents, you have to add up the exponents. Don't forget the numerical coefficients.
-3x² · 3x · 2x³ · x⁵ = -18x¹¹
2. There are two negative signs in this probem, meaning that they will cancel out. Multiply the rest like we did in the first problem.
3n² · -n² · -n³ = 3n⁷
Answer:
3234=264
Step-by-step explanation:
hope you find this helpfull
Answer:
a:3,11
Step-by-step explanation: