Remember you can do anything to an equation as long as you do it to both sides
and when multiply by negative, flip sign
8+h>2+3h
minus h both sides
8+h-h>2+3h-h
8+0>2+2h
8>2+2h
minus 2 both sides
8-2>2-2+2h
6>0+2h
6>2h
divide by 2 both sides
6/2>2h/2
3>1h
3>h
first opotin
The answer to the question is
-8 (3x-4)
Marie states that any integer greater than 4 will always get an even number of factors.
This can be proven wrong by (for example) 12.
12 has these factors:
1 x 12
2 x 6
3 x 4
12 has an ODD number of factor pairs.
Another example is 28.
28:
1 x 28
2 x 14
4 x 7
28 has an odd number of factor pairs.
I hope this helps!
Alright, so what we can take as a given is that arcDE/2= ∠CDE=2x+20 since the arc corresponding to the angle is 2*the angle. To solve for arcDE, we multiply both sides by 2 to get 2(2x+20)=4x+40=arcDE. Since the arcs in a circle add up to 360 degrees and we only have -20+30x and arcDE, we have -20+40+4x+30x=360 using the associative property. Simplifying, we get 20+34x=340. Subtracting 20 from both sides, we get 340=34x. Next, we can divide both sides by 34 to get 10=x.
