Answer:
401135 kJ
Explanation:
From the balanced quation,
(q/n) = CΔE
Molar heat of combustion = 7.85kJk × (303.81-298.70)k
= 7.85kj × 5.11
= 40.1135kj
Producers (autotroph)
I’m sorry if this isn’t the answer you were looking for, if so, please be more specific and I can try to help again, thank you.
Answer: After three half-lives 1/8 (12.5%) of the original sample remains