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hram777 [196]
3 years ago
13

Create and balance a chemical equation for the following statement.

Chemistry
1 answer:
m_a_m_a [10]3 years ago
8 0
FeCl₂  +  2NH₄OH  →  Fe(OH)₂  +  2NH₄Cl
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Is a neutron located in the inside or outside of the nucleus ?
vampirchik [111]
The neutron is inside the nucleus
6 0
3 years ago
Read 2 more answers
What mass of copper is produced when zinc is added to a solution containing 31.9g copper ii tetraoxosulphate vi
solmaris [256]

Answer:

12.7g of Cu

Explanation:

First let us generate a balanced equation for the reaction. This is illustrated below:

Zn + CuSO4 —> ZnSO4 + Cu

Molar Mass of Cu = 63.5g/mol

Molar Mass of CuSO4 = 63.5 + 32 + (16x4) = 63.5 + 32 + 64 = 159.5g/mol

From the equation,

159.5g of CuSO4 produced 63.5g of Cu.

Therefore, 31.9g of CuSO4 will produce = (31.9 x 63.5) / 159.5 = 12.7g of Cu

4 0
3 years ago
A bob of mass of 0.18 kilograms is released from a height of 45 meters above the ground level. What is the value of the kinetic
Drupady [299]

We can assume that all<span> gravitational potential energy is converted into kinetic energy of the object.</span><span>

<span>Hence, </span>GPE = KE

Where GPE is gravitational Potential Energy (J) and KE is Kinetic Energy (J)

GPE = mgh

<span>Where, m is the mass of the object (kg), g is acceleration due to gravity (9.8 m s</span></span>⁻<span>²) and h is the height to the<span> object from ground (m).</span></span><span>

m = 0.18 kg
g = 9.8 m s</span>⁻²<span>
h = 45 m

Hence, 
       GPE = 0.18 kg x 9.8 m s</span>⁻² x 45 m<span>
                = 79.38 J
                ≈ 79 J

<span>Hence, </span>KE = GPE = 79 J

<span>Hence, the answer is '79 joules'.</span></span>

8 0
3 years ago
The room temperature electrical conductivity of a semiconductor specimen is 2.8 x 104 (?-m)-1. The electron concentration is kno
Julli [10]

Answer:

7.43 × 10²⁴ m⁻³

Explanation:

Data provided in the question:

Conductivity of a semiconductor specimen, σ = 2.8 × 10⁴ (Ω-m)⁻¹

Electron concentration, n = 2.9 × 10²² m⁻³

Electron mobility, \mu_n = 0.14 m²/V-s

Hole mobility, \mu_p= 0.023 m²/V-s

Now,

σ = nq\mu_n+pq\mu_p

or

σ = q(n\mu_n+p\mu_p)

here,

q is the charge on electron = 1.6 × 10⁻¹⁹ C

p is the hole density

thus,

2.8 × 10⁴ = 1.6 × 10⁻¹⁹( 2.9 × 10²² × 0.14 +  p × 0.023 )

or

1.75 × 10²³ = 0.406 × 10²² + 0.023p

or

17.094 × 10²² = 0.023p

or

p = 743.217 ×  10²²

or

p = 7.43 × 10²⁴ m⁻³

5 0
4 years ago
An element has an atomic number of 22 what is the total number of valance electrons?
yuradex [85]

The Valance Electorns is 4

4 0
4 years ago
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