Answer:
67.5% ≅ 67.6%
Explanation:
Given data:
Mass of water = 17.0 g
Mass of oxygen produced (actual yield)= 10.2 g
Percent yield of oxygen = ?
Solution:
Chemical equation:
2H₂O → 2H₂ + O₂
Number of moles of water:
Number of moles = mass/ molar mass
Number of moles = 17.0 g/ 18.016 g/mol
Number of moles = 0.944 mol
Now we will compare the moles of oxygen with water to know the theoretical yield of oxygen.
H₂O : O₂
2 : 1
0.944 : 1/2×0.944 = 0.472 mol
Mass of oxygen:
Mass = number of moles× molar mass
Mass = 0.472 mol × 32 g/mol
Mass = 15.104 g
Percent yield:
Percent yield = [Actual yield / theoretical yield] × 100
Percent yield = [ 10.2 g/ 15.104 g] × 100
Percent yield = 0.675 × 100
Percent yield = 67.5%
Answer: The physical properties of iron oxide are that it is an odorless, red-brown solid, and that it is insoluble. Depending on the chemical formula, one of the chemical properties is its combustibility. If the chemical formula is Fe2O3, it is not combustible. If the formula is FeO, it is readily combustible.
Answer:
2HNO3 + Ba(OH)2 => Ba(NO3)2 + 2H2O
Explanation:
Answer:
NaCl + Fe2+ ---> FeCl2 + Na+
Single replacement
Explanation:
Na is replaced by Fe2+ to form FeCl2, and that is the only replacement. Thus, it is single replacement.
