24.305 g +28.08 g + 3(15.999 g)=100.382
219 g MgSIO3 (1 mole MGSIO3/100.382g)=2.181 mol MgSIO3
the answer is 2.18 mol MgSIO3
Answer:
It's B !
Explanation:
Formulas. The molecular formula for glucose is C6H12O6. This means that there are 6 carbon atoms, 12 hydrogen atoms, and 6 oxygen atoms bonded together to make one molecule of glucose.
Hope this helps!!
Answer:
See explanation
Explanation:
Now, the equation of the reaction is;
Cu(s) + 2AgNO3(aq) --------> Cu(NO3)3 (aq) + 2Ag(s)
Number of moles of silver precipitate = 0.24/108 g/mol= 0.0022 moles
Number of moles of AgNO3 = 50/1000 * 0.050 = 0.0025 Moles
If 2 moles of AgNO3 yields 2 moles of Ag
Then 0.0025 moles of AgNO3 yields 0.0025 * 2/2 = 0.0025 moles of Ag
Number of moles of Cu = 2.00g/63.5 g/mol = 0.03 moles
If 1 mole of Cu yields 2 moles of Ag
0.03 moles of Cu yields 0.03 moles * 2/1 = 0.06 moles of Ag
Hence AgNO3 is the limiting reactant
Theoretical yield of Ag = 0.0025 moles of Ag * 108 = 0.27 g
Actual yield of Ag = 0.24 g
Percent yield = actual yield/theoretical yield * 100
Percent yield = 0.24/0.27 * 100
Percent yield = 88.8%
Answer:
Heat transfer in the atmosphere from the equatorial regions to higher latitudes occurs through the process of Convection
Explanation:
The equatorial regions of the earth's surface receive the most heat from the sun than any other region of the earth. This is because the are most directly in line with the direct heat from the sun.
Due to this heat from the sun, atmospheric air around the equatorial regions are hot and less dense than air in regions of higher latitudes, and thus, rises above the equator. The rising air at the equator is replaced by colder and denser air from higher latitudes north and south of the equator. As the rising air of the equatorial regions are being replaced by colder and denser air from higher latitudes, the hot and humid air moves away from the equator, toward regions of higher latitude, north and south thereby setting up a convection current of heat flow.
