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BigorU [14]
2 years ago
5

I need help with this math problem

Mathematics
1 answer:
Mkey [24]2 years ago
8 0

Step-by-step explanation:

that is just a complicated way to ask, at what values of x is the functional value infinite ? or directly, for what values of x is the denominator of that fraction 0 ?

it is zero, if just one of the 3 factors is 0.

and that would happen for

x = 0

x = -6

x = 1

so, A, D and E are correct.

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3 0
3 years ago
Help please <br>I DONT understand <br>​
RideAnS [48]

Answer:

it is B i thinkif im wrong im sorry

Step-by-step explanation:

3 0
2 years ago
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Hello, I really need help with this!
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5 0
3 years ago
Given PA=13 in. and CB=15 in.<br><br> What is CA ?
alexandr1967 [171]

Triangles CPA and CPB are both right triangles. They share a leg, so that leg in one triangle is congruent to that leg in the other triangle. We are given that PA is congruent to PB by the hash marks on the diagram. Thus two legs and an included angle are congruent between the triangles.

... ∆CPA ≅ ∆CPB by the SAS postulate


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8 0
2 years ago
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RideAnS [48]

Answers:

  • System 1:  x = 3 and y = -5
  • System 2: x = 1 and y = 2

==========================================================

Explanation:

For now, let's focus on system 1.

We have identical copies of "2y" in each equation, which means that if we were to subtract the equations straight down, then the y terms cancel out. That allows us to solve for x.

  • The x terms subtract to 7x-x = 6x
  • The y terms subtract to 0 and go away
  • The right hand sides subtract to 11 minus (-7) = 11-(-7) = 11+7 = 18

After doing those subtractions, we have the new equation 6x = 18 which solves to x = 3. Divide both sides by 6 to isolate x.

Once we know x, we can find out y.

7x+2y = 11

7(3)+2y = 11

21+2y = 11

2y = 11-21

2y = -10

y = -10/2

y = -5

or we can say

x+2y = -7

3+2y = -7

2y = -7-3

2y = -10

y = -10/2

y = -5

We should lead to the same y value either way. This helps confirm we have the correct x value.

Overall, the solution to system 1 is (x,y) = (3, -5)

----------------------------

Now onto system 2.

Unfortunately, we don't have identical y terms this time. But what we can do is double everything in the second equation to go from -x+y = 1 to -2x+2y = 2.

The new equivalent system is

\begin{cases}7x+2y = 11\\-2x+2y = 2\end{cases}

Now we have the same situation as before: Subtract straight down, solve for x.

  • The x terms subtract to 7x-(-2x) = 7x+2x = 9x
  • The y terms go away when subtracting
  • The right hand sides subtract to 11-2 = 9

So we have 9x = 9 and that solves to x = 1.

We'll use this x to find the y value.

7x+2y = 11

7(1)+2y = 11

7+2y = 11

2y = 11-7

2y = 4

y = 4/2

y = 2

Or you could pick on the second equation

-x+y = 1

-1+y = 1

y = 1+1

y = 2

6 0
2 years ago
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