2x dx/dt +2y dy/dt = 0
<span>x dx/dt + y dy/dt = 0 </span>
<span>9*4 + 12 dy/dt = 0 </span>
<span>dy/dt = - 3 ft/sec </span>
27)
Equation of the existing water pipe's line
a) slope, m = rise / run = Δy / Δx = 3/2
b) y-intercept, b = 3
equation: y = mx + b = (3/2)x + 3
Equation of the new water pipe's line
slope, m = - 1 / (slope of the perpendicular line) = - 1 / (3/2) = - 2/3
point (0,2)
=> y - 2 = (-2/3) (x - 0) => y = (-2/3)x + 2 <---- equation of the new pipe
28)
two parallel lines have the same slope =>
slope, m = rise / run = Δy / Δx = [4 - 0] / [11 - 8] = 4 / 3
point (4,5) => y - 5 = (4/3) (x - 4)
=> y = (4/3)x - 16/3 + 5 = (4/3)x - 1/3
y = (4/3)x - 1/3 <--- equation of the new bike path
21. Broooooo, This is baby stuff!
Answer:
Step-by-step explanation:
f(x) = - | x + 2 | + 2
The vertex of the function is a <em>max of the function</em> at <em>( - 2 , 2 )</em>
