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nydimaria [60]
3 years ago
13

How to determine if an equation. is linear

Mathematics
1 answer:
cupoosta [38]3 years ago
3 0
Simplify it. if it has exponents it is not linear and if it doesn’t then it is linear
You might be interested in
You make 12 equal payments you pay a total of $1308. how much is each payment? step by step
klemol [59]

Answer:

1308/12=109

Step-by-step explanation:

each payment is 109 dollars

i just divided 1308 by 12 and got 109

8 0
2 years ago
Read 2 more answers
Consider the following hypothesis test H0 p 20 Ha p 20 A sample of 400 provided a sample proportion p 175 a Compute the value of
Bogdan [553]

Answer:

a) -1.25

b) 0.2112

c) -1.96

Step-by-step explanation:

Data provided in the question:

Sample size, n = 400

H0 : p = 20

\bar{p} = 175

Now,

a) The test statistic is  given as:

Z = \frac{(\bar{p}-p)}{\sqrt{\frac{p(1-p)}{n}}}

on substituting the respective values, we get

Z = \frac{(0.175-0.2)}{\sqrt{\frac{0.2\times0.8}{400}}}

= -1.25

b) The p-value = 2 × P(Z <-1.25)

Now from the standard normal table

P(Z <-1.25) = 10.56% = 0.1056

Thus,

p-value = 2 × 1056 = 0.2112

c) for a = 0.05,

the critical value is Z_{\frac{a}{2}}=Z_{\frac{0.05}{2}} i.e Z_{0.025}

Now from standard normal table

Z_{0.025} = -1.96

3 0
3 years ago
The distribution of passenger vehicle speeds traveling on a certain freeway in California is nearly normal with a mean of 73.7 m
umka2103 [35]

Answer:

a)  0.2347, 0.0007

b) 1.30

c) 0.63

Step-by-step explanation:

Given –  

Mean = 73.4

Sigma = 4.7

Probability that the speed is greater than 70 is  

P (X>70) = P (z> (70-73.4)/4.7) = P (z>-0.72) = 0.7653

a) The probability that a car is not speeding = 1 - 0.7653 = 0.2347

The probability that all 5 cars are not speeding = (0.2347)5 = 0.0007

b) E (X) = 1/p = 1/0.7653 = 1.30  

c) Standard deviation = Sqrt (1-p/p) = (1-0.7653)/0.7653 = 0.63

5 0
2 years ago
What is the product of 2x(x-4)
aliya0001 [1]

The answer to your question is 2x^2 - 8x

8 0
3 years ago
Three Linear Variables​
azamat

Answer:

23 yellow, 30 pink and 12 blue balls

Step-by-step explanation:

Let the number of yellow, pink, blue, and black balls be y, p, b, and x respectively.

<em>From 1st sentence:</em>

y +p +b +x= 90

<em>"</em><em>60</em><em> </em><em>of</em><em> </em><em>them</em><em> </em><em>are</em><em> </em><em>not</em><em> </em><em>pink</em><em>"</em><em> </em>

➜ y +b +x= 60

Given that 25 are black, x= 25.

<em>"</em><em>67</em><em> </em><em>of</em><em> </em><em>them</em><em> </em><em>are</em><em> </em><em>not</em><em> </em><em>yellow"</em>

➜ p +b +x= 67

Subst. x= 25 into the above equations:

y +p +b +25= 90

y+ p +b= 65 -----(1)

y +b +25= 60

y +b= 35 -----(2)

p +b +25= 67

p +b= 42 -----(3)

I will rewrite the 3 equations for better clarity:

y +p +b= 65 -----(1)

y +b= 35 -----(2)

p +b= 42 -----(3)

(1) -(2):

p= 65 -35

p= 30

(1) -(3):

y= 65 -42

y= 23

Substitute p= 30 and y= 23 into (1):

23 +30 +b= 65

b= 65 -53

b= 12

Thus, there 23, 30 and 12 yellow, pink and blue balls respectively.

8 0
2 years ago
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