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drek231 [11]
3 years ago
11

Find 6.3×10−59×10−3

Mathematics
1 answer:
iris [78.8K]3 years ago
3 0

Answer:

-5.3 x 10^2

Step-by-step explanation:

I believe that is the answer

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PLEASE DONT WASTE MY POINTS ITS THE 5TH TIME POSTING
emmasim [6.3K]

Given:

Initial cost of living = $44,000

Rate of increase = 5% = 0.05

To find:

The cost of living in 20 years.

Solution:

The exponential growth model is:

y=a(1+r)^t

Where, a is the initial value, r is the growth rate and t is the number of years.

Putting a=44000,r=0.05, t=20 in the above model, we get

y=44000(1+0.05)^{20}

y=44000(1.05)^{20}

y=116745.099026


y\approx 116745.10


Therefore, the cost of living in 20 years is about $116745.10.

5 0
3 years ago
(12 points) please help I'm very confused
Dafna1 [17]

First one is 15 over 32 . You have to do KEEP, CHANGE, FLIP . Keep the first fraction the same, change the division sign to a multiplication sign then flip the last fraction . 3 times 5 is 15. 8 times 4 is 32 .

7 0
3 years ago
Read 2 more answers
Simplify. 3.3÷(0.8−3)−0.5 Enter your answer in the box.
Veseljchak [2.6K]

Answer:

-2

Step-by-step explanation:

3.3÷(0.8−3)−0.5

First think of PEMDAS

So first do parenthese

(0.8-3)=-2.2

3.3÷-2.2-0.5

Now do division

3.3/-2.2=-1.5

and now subtraction

-1.5-0.5=-2


6 0
3 years ago
Read 2 more answers
Triangles ABC and DEF are similar.
Nookie1986 [14]
DF = 2.68
EF = 4.477611940298507
(I think)
4 0
3 years ago
Read 2 more answers
One week Beth bought 3 apples and 8 pears for 14.50. The next week she bought 6 apples and 4 pears and paid 14$ find the cost of
neonofarm [45]

Cost of 1 apple is $ 1.5 and cost of 1 pear is $ 1.25

<h3><u>Solution:</u></h3>

Let "a" be the cost of 1 apple

Let "p" be the cost of 1 pear

Given that,

<em><u>One week Beth bought 3 apples and 8 pears for 14.50</u></em>

So we can frame a equation as:

3 apples x cost of 1 apple + 8 pears x cost of 1 pear = 14.50

3 \times a + 8 \times p = 14.50

3a + 8p = 14.50 ----- eqn 1

<em><u>The next week she bought 6 apples and 4 pears and paid 14$</u></em>

So we can frame a equation as:

6 apples x cost of 1 apple + 4 pears x cost of 1 pear = 14

6 \times a + 4 \times p = 14

6a + 4p = 14 ---- eqn 2

<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "p"</u></em>

Multiply eqn 2 by 2

12a + 8p = 28 ---- eqn 3

Subtract eqn 1 from eqn 3

12a + 8p = 28

3a + 8p = 14.50

(-)----------------

9a = 13.5

<h3>a = 1.5</h3>

From eqn 1,

3a + 8p = 14.50

3(1.5) + 8p = 14.50

4.5 + 8p = 14.50

8p = 10

<h3>p = 1.25</h3>

<em><u>Thus we have:</u></em>

Cost of 1 apple is $ 1.5 and cost of 1 pear is $ 1.25

4 0
3 years ago
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