Given:
Initial cost of living = $44,000
Rate of increase = 5% = 0.05
To find:
The cost of living in 20 years.
Solution:
The exponential growth model is:

Where, a is the initial value, r is the growth rate and t is the number of years.
Putting
in the above model, we get




Therefore, the cost of living in 20 years is about $116745.10.
First one is 15 over 32 . You have to do KEEP, CHANGE, FLIP . Keep the first fraction the same, change the division sign to a multiplication sign then flip the last fraction . 3 times 5 is 15. 8 times 4 is 32 .
Answer:
-2
Step-by-step explanation:
3.3÷(0.8−3)−0.5
First think of PEMDAS
So first do parenthese
(0.8-3)=-2.2
3.3÷-2.2-0.5
Now do division
3.3/-2.2=-1.5
and now subtraction
-1.5-0.5=-2
DF = 2.68
EF = 4.477611940298507
(I think)
Cost of 1 apple is $ 1.5 and cost of 1 pear is $ 1.25
<h3><u>Solution:</u></h3>
Let "a" be the cost of 1 apple
Let "p" be the cost of 1 pear
Given that,
<em><u>One week Beth bought 3 apples and 8 pears for 14.50</u></em>
So we can frame a equation as:
3 apples x cost of 1 apple + 8 pears x cost of 1 pear = 14.50

3a + 8p = 14.50 ----- eqn 1
<em><u>The next week she bought 6 apples and 4 pears and paid 14$</u></em>
So we can frame a equation as:
6 apples x cost of 1 apple + 4 pears x cost of 1 pear = 14

6a + 4p = 14 ---- eqn 2
<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "p"</u></em>
Multiply eqn 2 by 2
12a + 8p = 28 ---- eqn 3
Subtract eqn 1 from eqn 3
12a + 8p = 28
3a + 8p = 14.50
(-)----------------
9a = 13.5
<h3>a = 1.5</h3>
From eqn 1,
3a + 8p = 14.50
3(1.5) + 8p = 14.50
4.5 + 8p = 14.50
8p = 10
<h3>p = 1.25</h3>
<em><u>Thus we have:</u></em>
Cost of 1 apple is $ 1.5 and cost of 1 pear is $ 1.25