Answer:
The electric potential of the uniformly charge disk is 1392.1 V
Explanation:
Electric potential, for a uniformly charged disk at a distance A, is given as;
Where;
σ is the charge density = 1.40 μC/m³
ε is the permittivity of free space = 8.85 x 10⁻¹²
A is the distance above the disk = 40 cm = 0.4 m
R is the radius of the disk = 0.12 m
Substitute in these values into the equation above, we will have
Therefore, the electric potential of the uniformly charge disk is 1392.1 V
Answer:
5.3 x 10⁻⁹ C
Explanation:
r = radius of cylindrical shell = 10⁻⁵ m
L = length = 0.32 m
A = area
Area is given as
A = 2πrL
A = 2 (3.14) (10⁻⁵) (0.32)
A = 20.096 x 10⁻⁶ m²
d = separation = 10⁻⁸ m
= dielectric constant = 4
Capacitance is given as
eq-1
V = Potential difference across the membrane = 74 mV = 0.074 Volts
Q = magnitude of charge on each side
Magnitude of charge on each side is given as
Q = CV
using eq-1
Inserting the values
Q = 5.3 x 10⁻⁹ C