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Radda [10]
4 years ago
6

Protons are what charged and electrons are what charged

Physics
2 answers:
anzhelika [568]4 years ago
7 0
Protons positive charge electrons negetive charge
liraira [26]4 years ago
6 0
Protons are positively charged and electrons are negatively charged
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The charge density of radius 12.0 cm isgiven by with a = 1.40 μC/m 3 and r ismeasured radially outward from theorigin. What is t
Zigmanuir [339]

Answer:

The electric potential of the uniformly charge disk is 1392.1 V

Explanation:

Electric potential, for a uniformly charged disk at a distance A, is given as;

V = \frac{\sigma}{2 \epsilon} [\sqrt{A^2 +R^2} -A]

Where;

σ is the charge density = 1.40 μC/m³

ε is the permittivity of free space = 8.85 x 10⁻¹²

A is the distance above the disk = 40 cm = 0.4 m

R is the radius of the disk = 0.12 m

Substitute in these values into the equation above, we will have

V = \frac{1.4 X 10^{-6}}{2X8,85X10^{-12}}[\sqrt{0.4^2 +0.12^2}-0.4] \\\\V = (79096.05)(0.0176) = 1392.1 V

Therefore, the electric potential of the uniformly charge disk is 1392.1 V

3 0
3 years ago
Average velocity can be calculated by dividing displacement over what? 
bekas [8.4K]
The answer is A a change in time
5 0
3 years ago
Read 2 more answers
Homocysteine is bad for the heart because it can .. ?
fiasKO [112]
B damage the protective layers of the artery walls, which can intimately lead to heart disease.
4 0
4 years ago
The membrane of the axon of a nerve cell is a thin cylindrical shell of radius r = 10-5 m, length L = 0.32 m, and thickness d =
maksim [4K]

Answer:

5.3 x 10⁻⁹ C

Explanation:

r = radius of cylindrical shell = 10⁻⁵ m

L = length = 0.32 m

A = area

Area is given as

A = 2πrL

A = 2 (3.14) (10⁻⁵) (0.32)

A = 20.096 x 10⁻⁶ m²

d = separation = 10⁻⁸ m

k_{appa} = dielectric constant = 4

Capacitance is given as

Q=\frac{k_{appa}\epsilon _{o}A}{d}                               eq-1

V = Potential difference across the membrane = 74 mV = 0.074 Volts

Q = magnitude of charge on each side

Magnitude of charge on each side is given as

Q = CV

using eq-1

Q=\frac{k_{appa} \epsilon _{o}AV}{d}

Inserting the values

Q=\frac{4 (8.85\times 10^{-12})(20.096\times 10^{-6})(0.074)}{10^{-8}}

Q = 5.3 x 10⁻⁹ C

4 0
3 years ago
If four students separately measure the density of a rock, and they all have very low percent
lesya692 [45]

Answer:

Their measured results are closer to the exact or true value. Hence, their measured value is considered to be more accurate.

Explanation:

Considering the situation described above, the accuracy of a measured value depicts how closely a measured value is to the accurate value.

Hence, since the students' measured values have very low percent differences, it shows the similarity of computations or estimates to the actual values, which in turn offers a smaller measurement error.

Therefore, their measured results are closer to the exact or true value, which implies that their measured value is considered to be more accurate.

7 0
3 years ago
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