It becomes a different element
Answer:a supposition or proposed explanation made on the basis of limited evidence as a starting point for further investigation.
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Answer:
The Republican party was formed because they wanted??????
Explanation:
ICD-10-CM codes are -S02.2XXA, W21.01XA, Y93.61, Y92.830
S02.2 for Fracture, Traumatic/Nasal (Bone(s)), ICD-10-CM Alphabetic Index. Both the open fracture code and the dislocation code are not reported. Only the fracture code is provided if a fracture and a dislocation happen at the same place. Search for "dislocation/with fracture" in the alphabetical index to be sent to a doctor. A closed fracture is a fracture with displacement. To report the conditions leading up to the injury, external cause codes are utilized. Look for Struck (accidentally) by/ball (struck) (thrown)/football W21.01 in the ICD-10-CM External Cause of Injuries Index. Seven characters are required in the Tabular List to finish the code. For the first encounter, X is utilized as a stand-in for character number six, and character number seven is given the letter A.
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<h3><em><u>given</u></em><em><u>:</u></em></h3>
<em><u>first</u></em><em><u> </u></em><em><u>trip</u></em><em><u>=</u></em><em><u> </u></em><em><u>5</u></em><em><u>0</u></em><em><u> </u></em><em><u>miles</u></em><em><u>.</u></em>
<em><u>second</u></em><em><u> </u></em><em><u>trip</u></em><em><u>=</u></em><em><u> </u></em><em><u>3</u></em><em><u>0</u></em><em><u>0</u></em><em><u> </u></em><em><u>miles</u></em><em><u>.</u></em>
<h3><em><u>to</u></em><em><u> </u></em><em><u>find</u></em><em><u>:</u></em></h3>
<em><u>his</u></em><em><u> </u></em><em><u>new</u></em><em><u> </u></em><em><u>time</u></em><em><u> </u></em><em><u>compared</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>old</u></em><em><u> </u></em><em><u>time</u></em><em><u>.</u></em>
<h3><em><u>solution</u></em><em><u>:</u></em></h3>
<em><u>Let speed of the 1st trip x miles / hr. and speed of the 2nd trip 3x / hr.</u></em>
<em><u>Speed = Distance/Time</u></em>
<em><u>So, times taken to covered a distance of 50 miles on his first trip = 50/x hr.</u></em>
<em><u>= 100/x hr</u></em>
<em><u>Therefore</u></em><em><u>,</u></em><em><u> </u></em><em><u>his new time compared with the old time was twice as much.</u></em>
<em><u>answer</u></em><em><u>=</u></em><em><u> </u></em><em><u>b</u></em><em><u>)</u></em><em><u> </u></em><em><u>twice</u></em><em><u> </u></em><em><u>as</u></em><em><u> </u></em><em><u>much</u></em>