Question

An object is dropped from a height of 288 feet. The equation, - 16t ^ 2 + 288t = h(t) represents the height, hof the object after tseconds. How long does it take the object to the ground?
0 seconds
16 seconds
18 seconds
88 seconds

Answer 1

18 seconds

Step-by-step explanation:

The object will reach the ground when its height h(t) = 0. Therefore, we can write

$h(t) = 288t - 16t^2 = 0 \Rightarrow 16t^2 = 288t$

Solving for t, we get

$16t = 288 \Rightarrow t = 18\:\text{s}$