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MatroZZZ [7]
3 years ago
8

Suppose a triangle reflects over the y-axis. Which describes how the transformation affects the coordinates of the vertices?

Mathematics
2 answers:
PolarNik [594]3 years ago
7 0

Answer:

a

Step-by-step explanation:

Art [367]3 years ago
3 0

Answer: OPTION A.

Step-by-step explanation:

By definition:

- When you reflect a figure, you flip it over a line of reflection, then, both figures will be in opposite directions.

- The image (which is the reflection) and the pre-image will have the same shape ad size.

- If a figure is reflected over the y-axis, then the sign of the x-coordinate is changed.

Keeping the above on mind, you can conclude that when a triangle is reflected over the y-axis the coordinates of the vertices are afectted as following:

- The y-coordinate is not changed.

- The sign of the x-coordinate is changed.

Then:

(x,y) → (-x,y)

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Answer:

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Step-by-step explanation:

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Let,

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3 years ago
Determine the equation of the tangent line to the given path at the specified value of t. (sin(7t), cos(7t), 2t9/2); t=1
Reptile [31]

Answer:

P(t) = {sin7, cos7, 2} + (7cos7, -7sin7, 9)(t-1)

Step-by-step explanation:

The equation of the tangent line to the given path at the specified value of t is expressed as;

P(t) = f(t0) + f'(t0)(t - t0)

f(t0) = (sin(7t), cos(7t), 2t^9/2)

at t0 = 1;

f(t0) = {sin7(1), cos7(1), 2(1)^9/2}

f(t0) = {sin7, cos7, 2}

f'(t0) = (7cos7t, -7sin7t, 9/2{2t^9/2-1}

f'(t0) = (7cos7t, -7sin7t, 9t^7/2}

If t0 = 1

f'(1) = (7cos7(1), -7sin7(1), 9(1)^7/2)

f'(1) =(7cos7, -7sin7, 9)

Substituting the given function into the tangent equation will give:

P(t) = f(t0) + f'(t0)(t - t0)

P(t)= {sin7, cos7, 2} + (7cos7, -7sin7, 9)(t-1)

The final expression gives the equation of the tangent line to the path.

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Answer:

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