The product of this reaction is a halohydrin as shown here.
<h3>What are the products?</h3>
We have a reaction that first involves the formation an alkene as the bases are used on the first substrate. The alkene that is thus created is now able to react with the bromine in water.
The first step of the reaction is where the multiple bond is created and this multiple bond is what can now go on to participate in a chemical reaction in the next step of the process of reaction as shown in the image.
Bromine in water is also hat we call bromine water. This bromine water is able to add across a double bond and when that happen we will have a saturated compound. This could also be regarded as halohydrin reaction.
Recall that the first step of the reaction of the alkene with bromine is the formation of a dibromide via the brominium intermediate. This is now followed by reaction with water to form the halohydrin product.
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Answer:
In pure water, at 25C, the [H3O+] and [OH-] ion concentrations are 1.0 x 10-7 M. The value of Kw at 25C is therefore 1.0 x 10-14. Although Kw is defined in terms of the dissociation of water, this equilibrium constant expression is equally valid for solutions of acids and bases dissolved in water.
Explanation:
Given that the drum is replaced each time before sampling, the selections are independent events. Then, the probability of the combined event is the product of each probability: (50/5000) * (50/5000) * (50/5000) = (1/100)^3 = 0.000001