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Elodia [21]
3 years ago
13

Answer please bruhs and wy7uhjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjt

Chemistry
2 answers:
cestrela7 [59]3 years ago
8 0

Answer:B

Explanation:

allsm [11]3 years ago
3 0

Answer:

it's going to be A trust me

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A 2.026g sample of a hydrate of sodium carbonate (Na2CO3) is heated to remove water. After heating, the mass of the sample is 0.
OLEGan [10]

Answer:

62.98 % of the sample of hydrate is water

Explanation:

Step 1: Data given

Mass of the sample of a hydrate of sodium carbonate (Na2CO3) = 2.026 grams

After heating, the mass of the sample is 0.750 g

Molar mass H2O = 18.02 g/mol

Step 2: Calculate mass of water

Mass water = mass of hydrate - mass of sample after heating

Mass water = 2.026 grams - 0.750 grams

Mass water = 1.276 grams

Step 3: Calculate mass % percent of water

Mass % of water = (mass of water / total mass hydrate) * 100 %

Mass % of water = (1.276 grams / 2.026 grams) *100 %

Mass % of water = 62.98 %

62.98 % of the sample of hydrate is water

7 0
3 years ago
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Which planet is sometimes called Uranus’s twin? Saturn Pluto Jupiter Neptune
sattari [20]

Neptune.

Because the size, mass, composition and rotation of Neptune and Uranus are very similar they're sometimes refered to as planetary twins.

7 0
3 years ago
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Oxidation number for O in: AIPO4
katen-ka-za [31]

Answer:

hi lol

Explanation:

rffgegerwgergergerg

5 0
3 years ago
B. What are some benefits, other than air-quality improvement, of<br> using alcohols in fuel?
kenny6666 [7]
Airaplanes!!!!!!!!!!!
3 0
3 years ago
vaporized at 100°C and 1 atmosphere pressure. Assuming ideal gas 1 g mole of water is behavior calculate the work done and compa
Vesna [10]

Answer:

q = 40.57 kJ; w = -3.10 kJ; strong H-bonds must be broken.

Explanation:

1. Heat absorbed

q = nΔH = 1 mol × (40.57 kJ/1 mol) = 40.57 kJ

2. Change in volume

V(water) = 0.018 L

pV = nRT

1 atm × V = 1 mol × 0.082 06 L·atm·K⁻¹mol⁻¹ × 373.15 K

V = 30.62 L

ΔV = V(steam) - V(water) = 30.62 L - 0.018 L = 30.60 L

3. Work done

w = -pΔV = - 1 atm × 30.60 L = -30.60 L·atm

w = -30.60 L·atm × (101.325 J/1 L·atm) = -3100 J = -3.10 kJ

4. Why the difference?

Every gas does 3.10 kJ of work when it expands at 100 °C and 1 atm.

The difference is in the heat of vaporization. Water molecules are strongly hydrogen bonded to each other, so it takes a large amount of energy to convert water from the liquid phase to the vapour phase.

7 0
4 years ago
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