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3 years ago

70.544 divided by 0.04?

Mathematics

2 answers:

Pepsi [2]3 years ago

6 0

Answer:

1763.6

Step-by-step explanation:

When dividing decimals you have to move the decimal point to the right by two decimal places and you use the algorithm method of division

Varvara68 [4.7K]3 years ago

4 0

Answer:

1763.6

Step-by-step explanation:

First you write it out as a fraction.

$\frac{70.544}{0.04}$

When dividing you dont want any decimals. So you would multiply it by a thousand as the numerator goes till tenthousandths place.

$\frac{70544}{40}$

Now all you do is long division

You get 1763.6

Hope This Helps!!

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Wgat is 5/6 of an hour and 1/3 of an hour and hiw did you get the final answer

sergeinik [125]

Answer:

5/6 minutes x 60 = 50

1/3 minutes x 60 = 20

I got my answer by multiplying by 60 since there are 60 min in one hour.

Using the keyword 'of" it means to multiply so multiply your two given numbers.

7 0

3 years ago

Read 2 more answers

!!PLEASE HELP ME ANSWER!!

Igoryamba

Answer:

$x = \sqrt{w(w+z)}$

Step-by-step explanation:

By the Pythagorean theorem, triangle BCD has

$y^2 = x^2 - w^2$

and triangle ABD has

$v^2 = y^2 + z^2$ .

Substituting the first equation into the second equation for $y^2$ gives the equation

$v^2 = (x^2 - w^2) + z^2$

Now triangle ABC has

$(w+z)^2 = x^2 + v^2$

Expanding out the left side, $w^2 + 2wz + z^2 = x^2 + v^2$ .

Now substitute the equation from before, $v^2 = x^2 - w^2 + z^2$ , into the new equation.

$w^2 + 2wz + z^2 = x^2 + (x^2 - w^2 + z^2)$

$w^2 + 2wz + z^2 =2x^2 - w^2 + z^2$

We work to isolate $x^2$ by adding $w^2$ to both sides of equation and subtracting $z^2$ from both sides.

$2w^2 + 2wz = 2x^2$

Divide both sides by 2 and you get $w^2 + wz = x^2$

Assume that x is positive and square root both sides to get the final result of

$x = \sqrt{w^2 + wz} = \sqrt{w(w+z)}$

4 0

3 years ago

Find the given derivative by finding the first few derivatives and observing the pattern that occurs. d103 dx103 (sin(x))

aleksandrvk [35]

To find $\frac{d^{103}}{dx^{103}} \left(\sin{(x)}\right)$ , we find the first few derivatives and observe the pattern that occurs.

$\frac{d}{dx} (\sin{(x)})=\cos{(x)} \\ \\ \frac{d^2}{dx^2} (\sin{(x)})= \frac{d}{dx} (\cos{(x)})=-\sin{(x)} \\ \\ \frac{d^3}{dx^3} (\sin{(x)})= -\frac{d}{dx} (\sin{(x)})=-\cos{(x)} \\ \\ \frac{d^4}{dx^4} (\sin{(x)})= -\frac{d}{dx} (\cos{(x)})=-(-\sin{(x)})=\sin{(x)} \\ \\ \frac{d^5}{dx^5} (\sin{(x)})= \frac{d}{dx} (\sin{(x)})=\cos{(x)}$

As can be seen above, it can be seen that the continuos derivative of sin (x) is a sequence which repeats after every four terms.

Thus,

$\frac{d^{103}}{dx^{103}} \left(\sin{(x)}\right)= \frac{d^{4(25)+3}}{dx^{4(25)+3}} \left(\sin{(x)}\right) \\ \\ = \frac{d^3}{dx^3} \left(\sin{(x)}\right)=-\cos{(x)}$

Therefore,

$\frac{d^{103}}{dx^{103}} \left(\sin{(x)}\right)=-\cos{(x)}$ .