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GenaCL600 [577]
2 years ago
14

Pythagorean theoremHow do you visualize it and and solve it drawn out​

Mathematics
1 answer:
Black_prince [1.1K]2 years ago
8 0

Answer:

so using the Pythagorean theorem is simple. what you want o do for this question is to make a graph to visualize it. since the top of the ladder is 7 feet up the house, you would go up 7 points, and its 2 1/2 feet from the house, you would move out 2 1/2 points. The ladders length is the hypotenuse, or the longer side that you get when you connect those two points.

Step-by-step explanation:

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How do I give an example of a positive and negative tempature that has a different of 5 degrees
love history [14]

Answer:

You could say +3 and -2 or +4 and -1

Step-by-step explanation:For example if you draw a number line

count 1 hump between each line.   it equals 5.

     |_______|_______|_______|_______|_______|

    -2            -1               0              1              2              3

4 0
3 years ago
Find the value of 4 + (27 - 12 ∙ 2) ÷ 2.
Stella [2.4K]
5.5 or 11/12 is the answer I believe 
3 0
3 years ago
Read 2 more answers
Pleaseee help me. Write an equation in one variable that has no solutions. The equation must require at least one step to be sol
AnnyKZ [126]

Answer:

2x+6=6+2x

   -6    -6

2x=2x

/2   /2

x=x

No solution

Step-by-step explanation:

6 0
4 years ago
Question 2 (2 points) Which point is the intersection of the graphs of this system of equations? 6x + 2y = -4 3x +2y = 8
sashaice [31]

Answer:

(x, y) =(-4,10)

Step-by-step explanation:

6x+2y=-4

3x+2y=8 /*(-1)

6x+2y=-4 (1)

-3x-2y=-8 (2)

6x+2x=-4

(1)+(2) 3x=-12

6x+2x=-4

x=-12/3

6x+2y=-4

x=-4

6*(-4)+2y=-4

x=-4

-24+2y=-4

x=-4

2y=-4+24

x=-4

2y=20 y=20/2 y=10

(x,y)=(-4,10)

3 0
4 years ago
Using the quadratic formula to solve x2 = 5 – x, what are the values of x? StartFraction negative 1 plus-or-minus StartRoot 21 E
Snezhnost [94]

Answer: StartFraction negative 1 plus-or-minus StartRoot 21 EndRoot Over 2

Step-by-step explanation:

The given quadratic equation is expressed as

x² = 5 - x

Rearranging the equation to take the standard form of ax² + bx + c, it becomes

x² + x - 5 = 0

The general formula for solving quadratic equations is expressed as

x = [- b ± √(b² - 4ac)]/2a

From the equation given,

a = 1

b = 1

c = - 5

Therefore,

x = [- 1 ± √(1² - 4 × 1 × - 5)]/2 × 1

x = [- 1 ± √(1 - - 20)]/2

x = [- 1 ± √21]/2

x = (- 1 + √21)/2 or x = (- 1 - √21)/2

3 0
3 years ago
Read 2 more answers
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