Answer:
a) <em>Mean number of beans = 33.4 per coco pad</em>
<em>b) Standard deviation of the beans = 5.2 per coco pad</em>
Step-by-step explanation:
<u><em>Step(i)</em></u>:-
a)
Given data 30, 28, 30, 35, 40, 25, 32, 36, 38 and 40.
mean of beans
x⁻ = ∑x/n
![x^{-} = \frac{30+ 28+30+35+40+25+32+36+38 + 40.}{10} = 33.4](https://tex.z-dn.net/?f=x%5E%7B-%7D%20%3D%20%5Cfrac%7B30%2B%2028%2B30%2B35%2B40%2B25%2B32%2B36%2B38%20%2B%2040.%7D%7B10%7D%20%3D%2033.4)
<em>Mean number of beans per coco pad = 33.4</em>
<em>step(ii):-</em>
<em>b) </em>
<u><em>standard deviation</em></u>
<em>∑(xi - x⁻)² = (30-33.4)²+ (28-33.4)²+(30-33.4)²+(35-33.4)²+(40-33.4)²+(25-33.4)²+(32-33.4)²+(36-33.4)²+ (38-33.4)²+(40-33.4)²</em>
<em>On calculation , we get</em>
<em> ∑(xi - x⁻)² = 242.4</em>
<em>standard deviation </em>
<em> = </em>
<em></em>
<em>Standard deviation of the beans (σ) = 5.2 per coco pad</em>