
Using the fact that cos is 2π-periodic, we have

That is,
for any
and integer
.

We get 2 solutions in the interval [0, 2π] for
and
,

Answer:
616
Step-by-step explanation:
The equation to find the area of a trapezoid is: A = ½ (b
+b²) h.
b1=43
b2=45
h=14
Plug the variables in and solve.




Note that 60 minutes is 1 standard deviation away from the mean and from recalling the 68-95-99.7 rule, the area that will remain is (100 - 68) = 32%. However, we only want the leftmost portion of this area, so the answer is 32%/2 = 16%.
<span>Choose D.</span>