Properties of Logs
logb(x/y) = log<span>bx</span> - log<span>by</span>.
therefore
log5 (4/7)= log5 (4)- log5 (7)
<span>Solve log 5 (4) and log 5 (7) with the base change of the logarithm</span>
<span>log 5 4 = log 4 / log 5 </span>
Use the calculator:
<span>
<span>log 5 4 =0.8613531161
</span></span>
log 5 7 = log 7 / log 5
<span>log 5 7 =1.2090619551</span>
<span>log5 (4/7)= log5
(4)- log5 (7)=-0.347708839</span>
Answer:
i have made it in above picture
The locker ? Can you explain more please .
Step-by-step explanation:
A(-2;1)
B (6;5)
(y-yA)/(yB-yA)= (x-xA)/(xB-xA)
(y-1)/4=(x+2)/8
8y-8=4x+8
8y=4x+16
y=½x+2 that is x-2y+4=0
