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My name is Ann [436]
3 years ago
15

Which of the statements best compares the pairs of perpendicular and parallel lines?

Mathematics
2 answers:
Sergeu [11.5K]3 years ago
8 0
Wich statements. Let me know

quester [9]3 years ago
7 0

Answer:

perpendicular lines intersect, and parallel lines never meet.

Step-by-step explanation:

this is pretty obvious in itself, not a whole lot of explainaton needed. parallel lines are exactly the same distance from each other and no matter how far they extend, they will never touch each other. perpendicular lines have 2 lines that intersect at a 90 degree angle, both vertically and horizontally. please mark brainliest.

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30 points for the correct answer
Dahasolnce [82]

Answer:

its either 2/9 or 2/3

Step-by-step explanation:

I solved the top part and got 2/3 and i solved the bottom part and got 1/3 and you can multiply 2/3 and 1/3 and got 2/9

3 0
2 years ago
In Exercises 1-20, find the midpoint M of the segment with the given endpoints.
EleoNora [17]
1.(-3/2,3)
2.(5/2,2)
3.(5,4)
4.(7/2,-1)
5.(9/2,-1)

I gave the midpoints what do you mean by the given endpoints
5 0
3 years ago
If Ab = 54, find MC.
AnnyKZ [126]

Answer:

MC = 45

Step-by-step explanation:

Δ ABH and Δ MCH are similar and the ratios of corresponding sides are equal, that is

\frac{AB}{MC} = \frac{AH}{MH} , substitute values

\frac{54}{MC} = \frac{6}{5} ( cross- multiply )

6MC = 270 ( divide both sides by 6 )

MC = 45

8 0
3 years ago
What is the slope of the line represented by the equation 2x+3y= –12 ? –32 –23 23 32
mr_godi [17]

Answer:

Option 2 - m=-\frac{2}{3} is the slope of the equation.

Step-by-step explanation:

Given : Equation 2x+3y=-12

To find : What is the slope of the line represented by the equation ?

Solution :

The slope form of line is y=mx+c

Equation 2x+3y=-12

Take 2x to another side,

3y=-12-2x

Divide 3 both side,

y=\frac{-12-2x}{3}

y=\frac{-2}{3}x-4

On comparing with general equation,

m=-\frac{2}{3} is the slope of the equation.

Therefore, option 2 is correct.

7 0
3 years ago
Read 2 more answers
An object of mass weighing 5.24 kilograms is raised to a height of 1.63 meters. What is the potential energy of the object at th
Trava [24]
<span>Find force,
9.8 m/s2 x 5.24 kg = </span><span>51.352 N </span>

Find work,
<span><span>51.352 N x 1.63 m=  </span><span>83.70 N*m


</span>
Example:
To solve this given word problem we can first identify the given and the apt formula to use in this phenomenon: Given: Force = 4, 500 N = 4, 500 kg-m/s^2 Acceleration = 5 m/s^2   </span>
<span>Formula: f=ma </span>
<span>Derivation: m = f/a </span>
<span>Solution: </span><span><span>
1.    </span>M = f/a</span> <span><span>
2.    </span>M = 4,500 kg-m/s^2 / 5 m/s^2</span> <span><span>
3.    </span>M = 900 kg  </span> 

<span>Hence, the object’s mass is </span>900 kg.<span>
</span>



6 0
3 years ago
Read 2 more answers
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