Answer:
The average velocity of the particle is
.
Step-by-step explanation:
In vector terms, the average velocity of a particle (
), in meters per second, at a given time change (
), in seconds:
(1)
Where
and
is the change in position for x and y axes, in meters.
![\Delta x = x(2) - x(1)](https://tex.z-dn.net/?f=%5CDelta%20x%20%3D%20x%282%29%20-%20x%281%29)
![\Delta x = (4\cdot 2 - 1)-(4\cdot 1 - 1)](https://tex.z-dn.net/?f=%5CDelta%20x%20%3D%20%284%5Ccdot%202%20-%201%29-%284%5Ccdot%201%20-%201%29)
![\Delta x = 4\,m](https://tex.z-dn.net/?f=%5CDelta%20x%20%3D%204%5C%2Cm)
![\Delta y = y(2) - y(1)](https://tex.z-dn.net/?f=%5CDelta%20y%20%3D%20y%282%29%20-%20y%281%29)
![\Delta y = 8\cdot (2)^{2}-8\cdot (1)^{2}](https://tex.z-dn.net/?f=%5CDelta%20y%20%3D%208%5Ccdot%20%282%29%5E%7B2%7D-8%5Ccdot%20%281%29%5E%7B2%7D)
![\Delta y = 24\,m](https://tex.z-dn.net/?f=%5CDelta%20y%20%3D%2024%5C%2Cm)
![\Delta t = 2\,s - 1\,s](https://tex.z-dn.net/?f=%5CDelta%20t%20%3D%202%5C%2Cs%20-%201%5C%2Cs)
![\Delta t = 1\,s](https://tex.z-dn.net/?f=%5CDelta%20t%20%3D%201%5C%2Cs)
![\vec v_{avg} = \left(\frac{4\,m}{1\,s}\right)\,\hat{i} + \left(\frac{24\,m}{1\,s} \right) \,\hat{j}](https://tex.z-dn.net/?f=%5Cvec%20v_%7Bavg%7D%20%3D%20%5Cleft%28%5Cfrac%7B4%5C%2Cm%7D%7B1%5C%2Cs%7D%5Cright%29%5C%2C%5Chat%7Bi%7D%20%2B%20%5Cleft%28%5Cfrac%7B24%5C%2Cm%7D%7B1%5C%2Cs%7D%20%5Cright%29%20%5C%2C%5Chat%7Bj%7D)
![\vec {v}_{avg} = 4\,\hat{i} +24\,\hat{j}\,\left[\frac{m}{s} \right]](https://tex.z-dn.net/?f=%5Cvec%20%7Bv%7D_%7Bavg%7D%20%3D%204%5C%2C%5Chat%7Bi%7D%20%2B24%5C%2C%5Chat%7Bj%7D%5C%2C%5Cleft%5B%5Cfrac%7Bm%7D%7Bs%7D%20%5Cright%5D)
A(1) = -2 x 5(1) - 1 = -11
A(4) = -2 x 5(4) -1 = -41
A(8) = -2 x 5(8) -1 = -81
Answer:
303.2 cubic inches
Step-by-step explanation:
20.6in × 3.8in ×2.9in + 3.7in × 7.1in × 2.9in
= answer
32 is your answer you have to subtract 10 from 42
Answer:
9.6cm
Step-by-step explanation: