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beks73 [17]
2 years ago
11

Ashley correctly answered 85% of the questions She had on her last math test if she missed six problems how many questions were

on the test
Mathematics
1 answer:
vovikov84 [41]2 years ago
3 0
Do 6÷0.15 and you get 40. Please give Brainliest I am so close to the next level.
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Please Help!!<br> Show all work pls! <br> #15
MrRissso [65]

Step-by-step explanation:

82 + 76 + 42 = 200

42 out of 200 hmmm

200 / 2 = 100

42 / 2 = 21

21 out of 100 = 42 out of 200

=

21%

7 0
3 years ago
Read 2 more answers
(10) Both red line and blue line trains left the station at 5:00 pm. If both
scoundrel [369]

Answer:

5:40

Step-by-step explanation:

This is a problem involving the least common difference.

If you know that the red and blue trains left at the same time at 5, you know that another red train will leave at 5:08. Another blue train at 5:10.

The way to solve this will be to write out the factors of 8 and 10 and find the smallest number that they overlap.

Red:

8, 16, 24, 32, 40, 48, 56, 64, 72, 80

Blue:

10, 20, 30, 40

You see that after 40 mnutes, they are both leaving the station again. After 40 minutes, at 5:40, they are both leaving.

6 0
2 years ago
300 + 40 + 7/10 + 5/100 + 3/1000
Zielflug [23.3K]

Answer:1 5/10

Step-by-step explanation:

300 + 40 = 340 + 7/10 + 5/100 turn simplify it to 7/10 + 5/10 + 3/10 =15/10  = 1 5/0

5 0
3 years ago
Read 2 more answers
(7^2)^4= n^8 solve for n
S_A_V [24]

Answer:

n=7

Step-by-step explanation:

(7^2)^4= n^8

We know that a^b^c = a^(b*c)

7^(2*4) = n^8

7^8 = n^8

Since the exponents are the same, the bases must be the same

n=7

4 0
2 years ago
Jeremiah is driving from Pensacola to Jacksonville. The graph shows his distance from Jacksonville. 36 E 320 28 240 20 160 120 4
3241004551 [841]
The speed is the change in position divided by the time.

There are four intervals where the speed is uniform:

1) from 0 to 0,5 hours
2) from 0,5 hours to 3 hours
3) from 3 to 4 hours
4) from 4 to 7 hours

We are asked to say the average speed during the interval in which J. is traveling the fastest.

That is where the is more inclined, and that happen in the last interval. There the speed is tha change in position / the time =
(200 -0)miles/3hours = 67 mph.

If you are not sure that this is the fastest speed, you can calculate the speed in the other intervals in the same way and compare.
8 0
3 years ago
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