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Viefleur [7K]
2 years ago
13

Write a program that reads a list of integers, one per line, until an * is read, then outputs those integers in reverse. For sim

plicity in coding output, follow each integer, including the last one, by a comma. Note: Use a while loop to output the integers. DO NOT use reverse() or reversed(). Ex: If the input is:
Computers and Technology
1 answer:
TiliK225 [7]2 years ago
8 0

Answer:

I'm just going to copy my pseudocode into an answer:

x = array()

i = 0

while (true)

j = input()

if j = "*" then break

x[i] = j

i++

print x.join(", ")

Explanation:

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make sure the speaker is clean and you volume setting is on normal there is alot of setting for deaf people so make sure that is correctly

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3 years ago
When working in Photoshop with the move tool, you can select multiple layers and use this option to arrange them into a straight
wel

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Distribute -  will put all of the layers in a straight line across the image

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When creating any digital work, what is the MOST important thing to remember?
kvasek [131]

Answer:

ALWAYS  double check your work

Explanation:

3 0
3 years ago
Write a function named “createPurchaseOrder” that accepts the quantity (integer), the cost per item(double), and the description
Leona [35]
#include
Program: using namespace std;
string createPurchaseOrder0;
int main(
{
cout<return 0;
}
string createPurchaseOrder(
{
int qty;
double costPerltem;
string description,info="":
cout<<"Enter Quantity:
cin>>qty;
cout<<"Enter cost per item: "
cin>>costPerltem;
cout<<"Enter Description: "
cin>>description;
if(qty<0 I| costPerltem<0
Idescription.compare(''"')==0)
cout<<'InThe entered data is invalid!":
info="":
else
"
cout<<"'InThe entered data is valid!":
info=info+"'(nQuantity: "+to_string (qty) +" In";
info=info+"Cost per item:
"†to_string (costPerltem)+"In";
info=info+"Description: "description+" In";
return info;

Output:
4 0
3 years ago
2. Consider a 2 GHz processor where two important programs, A and B, take one second each to execute. Each program has a CPI of
allsm [11]

Answer:

program A runs in 1 sec in the original processor and 0.88 sec in the new processor.

So, the new processor out-perform the original processor on program A.

Program B runs in 1 sec in the original processor and 1.12 sec in the new processor.

So, the original processor is better then the new processor for program B.

Explanation:

Finding number of instructions in A and B using time taken by the original processor :

The clock speed of the original processor is 2 GHz.

which means each clock takes, 1/clockspeed

= 1 / 2GH = 0.5ns

Now, the CPI for this processor is 1.5 for both programs A and B. therefore each instruction takes 1.5 clock cycles.

Let's say there are n instructions in each program.

therefore time taken to execute n instructions

= n * CPI * cycletime = n * 1.5 * 0.5ns

from the question, each program takes 1 sec to execute in the original processor.

therefore

n * 1.5 * 0.5ns = 1sec

n = 1.3333 * 10^9

So, number of instructions in each program is 1.3333 * 10^9

the new processor :

The cycle time for the new processor is 0.6 ns.

Time taken by program A = time taken to execute n instructions

=  n * CPI * cycletime

= 1.3333 * 10^9 * 1.1 * 0.6ns

= 0.88 sec

Time taken by program B = time taken to execute n instructions

= n * CPI * cycletime

= 1.3333 * 10^9 * 1.4 * 0.6

= 1.12 sec

Now, program A runs in 1 sec in the original processor and 0.88 sec in the new processor.

So, the new processor out-perform the original processor on program A.

Program B runs in 1 sec in the original processor and 1.12 sec in the new processor.

So, the original processor is better then the new processor for program B.

5 0
3 years ago
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