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USPshnik [31]
3 years ago
10

The reciprocal of a positIve natoinal number is?

Mathematics
1 answer:
sleet_krkn [62]3 years ago
3 0

Answer:

If the rational number is ab then, te reciprocal is ba

Step-by-step explanation:

Suppose that rational number is ab

Then, the reciprocal of that number is ba

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What is 4.3(v+2.5)=8.11+4v
True [87]

Answer:

-8.8

Step-by-step explanation:

We begin by simplifying the parenthesis through multiplication. Parenthesis is a structure which signals multiplication happening.

4.3(v+2.5)=8.11+4v\\4.3v+10.75=8.11+4v

We now begin combining like terms across the equal sign by performing the inverse or doing the opposite. Move first the 8.11 by subtracting it from both sides.

4.3v+10.75-8.11=8.11-8.11+4v\\4.3v+2.64=4v

Now, move 4.3v across by subtracting it from both sides.

4.3v-4.3v+2.64=4v-4.3v

2.64=-0.3v

Finally, we divide both sides by the coefficient of v.

\frac{2.64}{-0.3} =\frac{-0.3v}{-0.3} \\-8.8=v

6 0
3 years ago
Solve by using related function 1/2x^2 -2=0
Thepotemich [5.8K]

Answer:

1/2x^2-2=0

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-

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x=2,-2

4 0
3 years ago
$8.00+$6.00 = <br> answer
Lady bird [3.3K]

Answer:

$8.00+$3.00+$3.00=$14.00

Step-by-step explanation:

5 0
3 years ago
K12 math work need help MARK CROWN JUST NEED HELP
VladimirAG [237]

Answer:

60

Step-by-step explanation:

9 ÷ 15 = 0.6

Move decimal 2 places 0.6 -> 60

7 0
3 years ago
Read 2 more answers
A 2000-gallon metal tank to store hazardous materials was bought 15 years ago at cost of $100,000. What will a 5,000-gallon tank
harkovskaia [24]

Answer:

The value  is P_o = \$ 561958.9

Step-by-step explanation:

From the question we are told that

  The capacity of the metal  tank is  C =  2000 \  gallon

   The duration usage is  t = 15\ years \ ago

   The cost of 2000-gallon tank 15 years ago is P =  \$100,000

    The capacity of the second tank considered is C_1 = 5,000  

    The power sizing exponent is e = 0.57

     The initial construction cost index is  u_1 = 180

      The new construction after 15 years cost index is  u_2 =600

Equation for the power sizing exponent is mathematically represented as

      \frac{P_n}{P} = [\frac{C_1}{C} ]^{e}

=> Here P_n is the cost of 5,000-gallon tank as at 15 years ago  

So

     P_n  =  [\frac{5000}{2000} ] ^{0.57} * 100000

      P_n  =  \$168587.7

Equation for the cost index exponent is mathematically represented as

      \frac{P_o}{P_n}  =  \frac{u_2}{u_1}

HereP_o is the cost of 5,000-gallon tank today

So

       \frac{P_o}{168587.7}  =  \frac{600}{180}

=>    P_o = \frac{600}{180} * 168587.7

=>      P_o = \$ 561958.9

8 0
3 years ago
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