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2 years ago

Convert the fraction 2/5 to a decimal and a percent. Show all of your work and explain your answer.

Mathematics

2 answers:

Zigmanuir [339]2 years ago

6 0

The answer would be .40 or 40%.

2 x 5 = 10

2 x 2 = 4.

4/10

4/10 = 40% or .40

Zielflug [23.3K]2 years ago

3 0

To the convert 2/5 to a decimal it will be 0.40 because during when you do 5 do x20 so 1/5 = 0.20 and so on
for the percent it may be 40% but idk

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A bird is 4 meters from the ground. The bird is 74 cm higher from the ground than a squirrel that is sitting in a tree. How far

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2 years ago

Which statement describes the inverse of m(x) = x^2 – 17x?

DochEvi [55]

Given:

The function is

$m(x)=x^2-17x$

To find:

The inverse of the given function.

Solution:

We have,

$m(x)=x^2-17x$

Substitute m(x)=y.

$y=x^2-17x$

Interchange x and y.

$x=y^2-17y$

Add square of half of coefficient of y , i.e., $\left(\dfrac{-17}{2}\right)^2$ on both sides,

$x+\left(\dfrac{-17}{2}\right)^2=y^2-17y+\left(\dfrac{-17}{2}\right)^2$

$x+\left(\dfrac{17}{2}\right)^2=y^2-17y+\left(\dfrac{17}{2}\right)^2$

$x+\left(\dfrac{17}{2}\right)^2=\left(y-\dfrac{17}{2}\right)^2$ $[\because (a-b)^2=a^2-2ab+b^2]$

Taking square root on both sides.

$\sqrt{x+\left(\dfrac{17}{2}\right)^2}=y-\dfrac{17}{2}$

Add $\dfrac{17}{2}$ on both sides.

$\sqrt{x+\left(\dfrac{17}{2}\right)^2}+\dfrac{17}{2}=y$

Substitute $y=m^{-1}(x)$ .

$m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}$

We know that, negative term inside the root is not real number. So,

$x+\left(\dfrac{17}{2}\right)^2\geq 0$

$x\geq -\left(\dfrac{17}{2}\right)^2$

Therefore, the restricted domain is $x\geq -\left(\dfrac{17}{2}\right)^2$ and the inverse function is $m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}$ .

Hence, option D is correct.

Note: In all the options square of $\dfrac{17}{2}$ is missing in restricted domain.

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2 years ago

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Step-by-step explanation:

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2 years ago

Expand and simplify 4(x-2)+7(x-1)

Zolol [24]

Answer:

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Step-by-step explanation:

4x-8+7x-7

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2 years ago

This composite shape is a rectangle with a semicircle attached on one end. The diameter of the semicircle is 6 feet.

Ugo [173]

As we can see on the picture we have a rectangle and half of circle.

The areas for half circle and rectangle are:

$A_{rectangle}=a\cdot b \\A_{halfcircle}=\frac{A_{circle}}{2}=\frac{\pi r^2}{2}$

The area of the figure is the sum of the area of half circle and rectangle. Also the height of a rectangle (6ft) is a diameter of a half circle therefore the radius of half circle is 6ft ÷ 2 = 3ft.

Now we calculate the areas.

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The area of the figure is approximately 74ft squared.

Hope this helps.

r3t40

3 0

2 years ago

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